Hi 2009/9/23 blumenkraft <vohs...@gmail.com>: > Hi, > > I have some list: > x = [8, 9, 1, 7] > and list of indices I want to delete from x: > indices_to_delete = [0, 3], so after deletion x must be equal to [9, > 1]. > > What is the fastest way to do this? Is there any builtin?
Try this- >>> x = [8, 9, 1, 7] >>> [x.pop(i) for i in sorted(indices_to_delete,reverse=True)] [7, 8] >>> x [9, 1] Built-in used here is `sorted' and method on list used here is `pop'. With regards to efficiency you may want to use the methods of list which is more intuitive afaik and useful as its more reflective of effect on the type list. It's a trivial choice here but later it might help. -- Regards, Ishwor Gurung -- http://mail.python.org/mailman/listinfo/python-list
