On Mon, 23 Feb 2009 00:06:58 -0800, neoedmund wrote:
> see the 3 small piece of code, i cannot understand why it result as
> this.
>
> 1.
> def test():
> abc="111"
> def m1():
> print(abc)
> m1()
> test()
>
> Output: 111
abc is local to test(). print(abc) looks f
En Mon, 23 Feb 2009 06:06:58 -0200, neoedmund
escribió:
it seems "you cannot change the outter scope values but can use it
readonly."
Exactly.
Python doesn't have variable "declarations" - so the compiler uses this
rule: "if the variable is assigned to, anywhere in the function body, it's
On Mon, Feb 23, 2009 at 12:06 AM, neoedmund wrote:
> see the 3 small piece of code, i cannot understand why it result as
> this.
>
> 1.
> def test():
>abc="111"
>def m1():
>print(abc)
>m1()
> test()
>
> Output: 111
>
> 2.
> def test():
>abc="111"
>
see the 3 small piece of code, i cannot understand why it result as
this.
1.
def test():
abc="111"
def m1():
print(abc)
m1()
test()
Output: 111
2.
def test():
abc="111"
def m1():
print(abc)
abc+="222"
