En Mon, 23 Feb 2009 06:06:58 -0200, neoedmund <neoedm...@gmail.com>
escribió:
it seems "you cannot change the outter scope values but can use it
readonly."
Exactly.
Python doesn't have variable "declarations" - so the compiler uses this
rule: "if the variable is assigned to, anywhere in the function body, it's
local". This is done by static analysis when the code is compiled.
2.
def test():
abc="111"
def m1():
print(abc)
abc+="222"
m1()
test()
Output:
print(abc)
UnboundLocalError: local variable 'abc' referenced before assignment
abc is assigned to, so it is local (and different from the abc in its
enclosing scope). You can't print abc until it is assigned "something".
3.
def test2():
abc=[111]
def m1():
print(abc)
abc.append(222)
m1()
print(abc)
No assignment to abc, so it's not local; print(abc) starts looking for it
in all the enclosing scopes (up to the module global scope, and last, the
builtin module).
--
Gabriel Genellina
--
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