thanks. that did the trick. in case anyone else is in the same boat as
myself, here are the relevant correspondences:
string <-> [int] bytes <-> [int]
---
--
lambda string: [ord(x) for x in string] list
lambda ints: ''.join([chr(x
On Mon, 02 Nov 2009 20:30:00 -0800, Sean McIlroy wrote:
> hello
>
> how do i say "chr" and "ord" in the new python?
"chr" and "ord".
> the functions below (which work in 2.6.6)
Can I borrow your time machine, there's some lottery numbers I want to
get.
There is no Python 2.6.6. The lates
Sean McIlroy writes:
> how do i say "chr" and "ord" in the new python?
By “the new python”, what do you mean?
* Python 2.6.4, the newest released version.
* Python 2.7, a currently in-development version.
* Python 3.1, another new release (but not the latest).
* Python 3.2, a currently in-devel
On Mon, Nov 2, 2009 at 11:30 PM, Sean McIlroy wrote:
> hello
>
> how do i say "chr" and "ord" in the new python? the functions below
> (which work in 2.6.6) show what i'm trying to do. thanks if you can
> help.
>
> def readbytes(filepath):
> return [ord(x) for x in open(filepath,'rb').read()]
>
hello
how do i say "chr" and "ord" in the new python? the functions below
(which work in 2.6.6) show what i'm trying to do. thanks if you can
help.
def readbytes(filepath):
return [ord(x) for x in open(filepath,'rb').read()]
def writebytes(numbers,filepath):
open(filepath,'wb').write(''.
