DUH. Thanks.
can't beleive I missed that one...
Alex
--
http://mail.python.org/mailman/listinfo/python-list
On 2005-02-18, imphasing <[EMAIL PROTECTED]> wrote:
> Whenever I try to open a file inside a subroutine, like so:
>
> def open():
> filePath=askopenfilename()
>
> fileOpen = open(filePath, "r")
> fileContent = fileOpen.read()
> fileOpen.close()
>
> it tells me that "open() t
Whenever I try to open a file inside a subroutine, like so:
def open():
filePath=askopenfilename()
fileOpen = open(filePath, "r")
fileContent = fileOpen.read()
fileOpen.close()
it tells me that "open() takes no arguments (2 given)"
Why is that? and how can I get a