On 2005-02-18, imphasing <[EMAIL PROTECTED]> wrote:
> Whenever I try to open a file inside a subroutine, like so:
>
> def open():
> filePath=askopenfilename()
>
> fileOpen = open(filePath, "r")
> fileContent = fileOpen.read()
> fileOpen.close()
>
> it tells me that "open() takes no arguments (2 given)"
> Why is that?
Because you defined open() as taking no arguments. You're
calling your own open() function, not the builtin one.
> and how can I get around that so I can open a file in a
> subroutine?
Don't call your function open().
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