On Fri, 18 Dec 2009 23:00:42 -, David Robinow
wrote:
I won't engage in any arguments about pythonicity but it seems simpler
if you convert to a list of tuples right away.
d = {1:('a', 1, 12), 5:('r',21,10), 2:('u',9,8)}
l = [(x, d[x]) for x in d.keys()]
which is a long way of writing "
Rory Campbell-Lange writes:
> I'm a bit rusty, and have just picked up the new "Learning Python" book
> but I'm finding that it isn't providing a useful refresher to the
> language or a particularly good introduction to version 3. Have you any
> suggestions.
While you aren't addressing me, I do
> mylist = [z for z in zip(list(d), list(d.values()))]
> The Pythonic way for the above line is:
> >>> mylist = list(d.items())
Quite right. Thanks for pointing that out.
I liked Chris Kaynor's solution:
s = sorted(d.items(), key=lambda i: i[1][2])
I'm a bit rusty, and have just picked up
Il Sat, 19 Dec 2009 17:30:27 +1100, Lie Ryan ha scritto:
> On 12/19/2009 9:34 AM, mattia wrote:
>> Can you provide me a much pythonic solution (with comments if possible,
>> so I can actually learn something)?
>
> If you only need to get i'th element sometimes, sorting the dict is
> fine. Otherwi
On 12/19/2009 9:34 AM, mattia wrote:
Can you provide me a much pythonic solution (with comments if possible,
so I can actually learn something)?
If you only need to get i'th element sometimes, sorting the dict is
fine. Otherwise, you might want to use collections.OrderedDict.
--
http://mail.p
Rory Campbell-Lange wrote:
On 18/12/09, mattia (ger...@gmail.com) wrote:
Hi all, I have a dictionary that uses dates and a tuples ad key, value
pairs. I need to sort the values of the dict and insert everything in a
tuple. The additional problem is that I need to sort the values looking
at the
On 18/12/09, mattia (ger...@gmail.com) wrote:
> Hi all, I have a dictionary that uses dates and a tuples ad key, value
> pairs. I need to sort the values of the dict and insert everything in a
> tuple. The additional problem is that I need to sort the values looking
> at the i-th element of the
Il Fri, 18 Dec 2009 18:00:42 -0500, David Robinow ha scritto:
> On Fri, Dec 18, 2009 at 5:34 PM, mattia wrote:
>> Hi all, I have a dictionary that uses dates and a tuples ad key, value
>> pairs. I need to sort the values of the dict and insert everything in a
>> tuple. The additional problem is t
On Fri, Dec 18, 2009 at 5:34 PM, mattia wrote:
> Hi all, I have a dictionary that uses dates and a tuples ad key, value
> pairs. I need to sort the values of the dict and insert everything in a
> tuple. The additional problem is that I need to sort the values looking
> at the i-th element of the l
Actually, in order to use duplicate values I need something like:
>>> import copy
>>> d = {1:('a', 1, 12), 5:('r', 21, 10), 2:('u', 9, 8), 3:('u', 9, 8) }
>>> dc = copy.deepcopy(d)
>>> t = [x for x in d.values()]
>>> def third(mls):
... return mls[2]
...
>>> s = sorted(t, key=third)
>>> pres =
I'd write it as:
s = sorted(d.iteritems(), key=lambda i: i[1][2])
If using python 3, it should be d.items() instead of d.iteritems().
d.iteritems() is a generator yielding tuples of (key, value) from
the dictionary 'd'.
lambda i: i[1][2] is the same as:
def sort_(i):
return i[1][2]
but in-lin
Hi all, I have a dictionary that uses dates and a tuples ad key, value
pairs. I need to sort the values of the dict and insert everything in a
tuple. The additional problem is that I need to sort the values looking
at the i-th element of the list. I'm not that good at python (v3.1), but
this is
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