On Fri, 18 Dec 2009 23:00:42 -0000, David Robinow <drobi...@gmail.com>
wrote:
I won't engage in any arguments about pythonicity but it seems simpler
if you convert to a list of tuples right away.
d = {1:('a', 1, 12), 5:('r',21,10), 2:('u',9,8)}
l = [(x, d[x]) for x in d.keys()]
which is a long way of writing "l = d.items()", or "l = list(d.items())"
if you're using Python 3. :-)
def third(q):
return q[1][2]
s = sorted(l, key=third)
print s
--
Rhodri James *-* Wildebeeste Herder to the Masses
--
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