On 14Oct2012 19:27, Ian Kelly wrote:
| On Sun, Oct 14, 2012 at 7:08 PM, Cameron Simpson wrote:
| > Is attr_name omitted from locals() in made_file_property _because_ I
| > have an assignment statement?
|
| Yes. Syntactically, a variable is treated as local to a function if
| it is assigned to s
On Sun, Oct 14, 2012 at 7:08 PM, Cameron Simpson wrote:
> On 14Oct2012 18:32, Ian Kelly wrote:
> | 'attr_name' is not in locals because while it's a local variable, it
> | has not been assigned to yet. It has no value and an attempt to
> | reference it at that point would result in an UnboundLoc
On 14Oct2012 18:32, Ian Kelly wrote:
| On Sun, Oct 14, 2012 at 3:54 PM, Cameron Simpson wrote:
| > | You assign to it, but there's no nonlocal declaration, so Python thinks
| > | it's a local var, hence your error.
| >
| > But 'unset_object' is in locals(). Why one and not the other?
| > Obvious
On Sun, Oct 14, 2012 at 3:54 PM, Cameron Simpson wrote:
> | You assign to it, but there's no nonlocal declaration, so Python thinks
> | it's a local var, hence your error.
>
> But 'unset_object' is in locals(). Why one and not the other?
> Obviously there's something about closures here I'm missi
On 13Oct2012 22:07, Chris Rebert wrote:
| On Saturday, October 13, 2012, Cameron Simpson wrote:
| > I'm having some trouble with closures when defining a decorator.
|
|
| > However, I can't make my make_file_property function work. I've stripped
| > the code down and it does this:
|
|
| > Tr
On Saturday, October 13, 2012, Cameron Simpson wrote:
> I'm having some trouble with closures when defining a decorator.
> However, I can't make my make_file_property function work. I've stripped
> the code down and it does this:
> Traceback (most recent call last):
> File "foo.py", li
