On Sun, Oct 14, 2012 at 3:54 PM, Cameron Simpson <c...@zip.com.au> wrote: > | You assign to it, but there's no nonlocal declaration, so Python thinks > | it's a local var, hence your error. > > But 'unset_object' is in locals(). Why one and not the other? > Obviously there's something about closures here I'm missing.
'unset_object' is in locals because it's a free variable and those are included in locals(), and it has a value. 'attr_name' is not in locals because while it's a local variable, it has not been assigned to yet. It has no value and an attempt to reference it at that point would result in an UnboundLocalError. -- http://mail.python.org/mailman/listinfo/python-list
