On Sun, Feb 12, 2017 at 4:29 AM, Chris Angelico wrote:
> Registry subkeys aren't paths, and the other two cases are extremely
> narrow. Convert slashes to backslashes ONLY in the cases where you
> actually need to.
\\?\ paths are required to exceed MAX_PATH (a paltry 260 characters)
or to avoid q
On Mon, 13 Feb 2017 11:43 am, Chris Angelico wrote:
> On Mon, Feb 13, 2017 at 11:40 AM, Erik wrote:
>> FWIW, if you'd have written the above as your first response I wouldn't
>> have argued ;) You alluded to it, for sure ... :D
>
> Nothing wrong with respectfully arguing. It's one of the best wa
On Mon, Feb 13, 2017 at 11:40 AM, Erik wrote:
> FWIW, if you'd have written the above as your first response I wouldn't have
> argued ;) You alluded to it, for sure ... :D
Nothing wrong with respectfully arguing. It's one of the best ways to
zero in on the truth :)
ChrisA
--
https://mail.python
On 13/02/17 00:34, Chris Angelico wrote:
The unit "\t" always means U+0009, even if it's following a raw string
literal; and the unit "\d" always means "\\d", regardless of the
rawness of any of the literals involved. The thing that's biting you
here is that unrecognized escapes get rendered as b
On Mon, Feb 13, 2017 at 11:34 AM, Erik wrote:
> OK, I get it now - because '\d' is not a valid escape sequence, then even in
> a non-raw string literal, the '\' is treated as a literal backslash
> character (not an escape).
>
> So, the second string token is NOT being treated as "raw", it just loo
On 13/02/17 00:23, Erik wrote:
r"hello \the" "worl\d" "\t"
'hello \\theworl\\d\t'
The initial string is raw. The following string adopts that (same as the
second example), but the _next_ string does not!
Why is the first string token parsed as a "raw" string, the second
string token also pars
On Mon, Feb 13, 2017 at 11:29 AM, Erik wrote:
> On 13/02/17 00:13, Chris Angelico wrote:
>>
>> On Mon, Feb 13, 2017 at 11:11 AM, Chris Angelico wrote:
>>>
>>> The string "\t" gets shown in the repr as "\t". It is a string
>>> consisting of one character, U+0009, a tab. The string r"\t" is shown
>
On 13/02/17 00:13, Chris Angelico wrote:
On Mon, Feb 13, 2017 at 11:11 AM, Chris Angelico wrote:
The string "\t" gets shown in the repr as "\t". It is a string
consisting of one character, U+0009, a tab. The string r"\t" is shown
as "\\t" and consists of two characters, REVERSE SOLIDUS and LATI
On 13/02/17 00:11, Chris Angelico wrote:
Firstly, be aware that there's no such thing as a "raw string" - what
you have is a "raw string literal". It's a purely syntactic feature.
I do understand that. When I said "is raw"/"rawness", I am talking about
what the _parser_ is doing. I don't think
On Mon, Feb 13, 2017 at 11:11 AM, Chris Angelico wrote:
> The string "\t" gets shown in the repr as "\t". It is a string
> consisting of one character, U+0009, a tab. The string r"\t" is shown
> as "\\t" and consists of two characters, REVERSE SOLIDUS and LATIN
> SMALL LETTER T. That might be why
On Mon, Feb 13, 2017 at 10:56 AM, Erik wrote:
> Actually, while contriving those examples, I noticed that sometimes when
> using string literal concatenation, the 'rawness' of the initial string is
> sometimes applied to the following string and sometimes not:
>
"hello \the" r"worl\d"
> 'hell
On 12/02/17 23:56, Erik wrote:
r"hello \the" "worl\d"
'hello \\theworl\\d'
Slightly surprising. The concatenated string adopts the initial string's
'rawness'.
"hello \the" r"worl\d" "\t"
'hello \theworl\\d\t'
The initial string is not raw, the following string is. The string
following _that
On 12/02/17 04:53, Steve D'Aprano wrote:
py> s = r'documents\'
File "", line 1
s = r'documents\'
^
SyntaxError: EOL while scanning string literal
(I still don't understand why this isn't just treated as a bug in raw string
parsing and fixed...)
I would imagine that i
On Sun, 12 Feb 2017 03:20 pm, eryk sun wrote:
> On Sun, Feb 12, 2017 at 3:52 AM, Steve D'Aprano
> wrote:
>> In Python, you should always use forward slashes for paths, even on
>> Windows.
>
> There are cases where slash doesn't work (e.g. some command lines;
> \\?\ prefixed paths; registry subke
On Sun, Feb 12, 2017 at 3:20 PM, eryk sun wrote:
> On Sun, Feb 12, 2017 at 3:52 AM, Steve D'Aprano
> wrote:
>> In Python, you should always use forward slashes for paths, even on Windows.
>
> There are cases where slash doesn't work (e.g. some command lines;
> \\?\ prefixed paths; registry subkey
On Sun, Feb 12, 2017 at 3:52 AM, Steve D'Aprano
wrote:
> In Python, you should always use forward slashes for paths, even on Windows.
There are cases where slash doesn't work (e.g. some command lines;
\\?\ prefixed paths; registry subkey paths), so it's simpler to follow
a rule to always convert
On Sat, 11 Feb 2017 05:11 am, epro...@gmail.com wrote:
> Hello NG
>
> Python 3.5.2
>
> Windows 10
>
> os.path.isfile() no recognise file with double dot?
>
> eg. match.cpython-35.pyc
I doubt that very much. I expect you are probably writing something like
this:
path = 'My Documents\testin
On Sat, 11 Feb 2017 06:50 am, Vincent Vande Vyvre wrote:
> Le 10/02/17 à 19:11, epro...@gmail.com a écrit :
>> Hello NG
>>
>> Python 3.5.2
>>
>> Windows 10
>>
>> os.path.isfile() no recognise file with double dot?
>>
>> eg. match.cpython-35.pyc
>>
>> Please somebody know something about that?
>>
>
On Fri, Feb 10, 2017 at 9:09 PM, Vincent Vande Vyvre
wrote:
> Le 10/02/17 à 22:03, Vincent Vande Vyvre a écrit :
>> Le 10/02/17 à 21:36, Peter Otten a écrit :
>>> Vincent Vande Vyvre wrote:
Le 10/02/17 à 19:11, epro...@gmail.com a écrit :
>
> Python 3.5.2
>
> Windows 10
>
Le 10/02/17 à 22:03, Vincent Vande Vyvre a écrit :
Le 10/02/17 à 21:36, Peter Otten a écrit :
Vincent Vande Vyvre wrote:
Le 10/02/17 à 19:11, epro...@gmail.com a écrit :
Hello NG
Python 3.5.2
Windows 10
os.path.isfile() no recognise file with double dot?
eg. match.cpython-35.pyc
Please s
Le 10/02/17 à 21:36, Peter Otten a écrit :
Vincent Vande Vyvre wrote:
Le 10/02/17 à 19:11, epro...@gmail.com a écrit :
Hello NG
Python 3.5.2
Windows 10
os.path.isfile() no recognise file with double dot?
eg. match.cpython-35.pyc
Please somebody know something about that?
Thank You in adv
Vincent Vande Vyvre wrote:
> Le 10/02/17 à 19:11, epro...@gmail.com a écrit :
>> Hello NG
>>
>> Python 3.5.2
>>
>> Windows 10
>>
>> os.path.isfile() no recognise file with double dot?
>>
>> eg. match.cpython-35.pyc
>>
>> Please somebody know something about that?
>>
>> Thank You in advance
>>
> In
On 2017-02-10 19:50, Vincent Vande Vyvre wrote:
Le 10/02/17 à 19:11, epro...@gmail.com a écrit :
Hello NG
Python 3.5.2
Windows 10
os.path.isfile() no recognise file with double dot?
eg. match.cpython-35.pyc
Please somebody know something about that?
Thank You in advance
Interesting, you'
On Sat, Feb 11, 2017 at 6:50 AM, Vincent Vande Vyvre
wrote:
> Interesting, you're right.
>
> Python 3.4.3 (default, Nov 17 2016, 01:08:31)
> [GCC 4.8.4] on linux
> Type "help", "copyright", "credits" or "license" for more information.
import os
os.path.isfile('/home/vincent/oqapy-3/
Le 10/02/17 à 19:11, epro...@gmail.com a écrit :
Hello NG
Python 3.5.2
Windows 10
os.path.isfile() no recognise file with double dot?
eg. match.cpython-35.pyc
Please somebody know something about that?
Thank You in advance
Interesting, you're right.
Python 3.4.3 (default, Nov 17 2016, 01
Hi Cameron,
Ok, i'll try that :)
Thanks
Smaine
Selon Cameron Simpson :
> On 30Dec2010 09:36, smain...@free.fr wrote:
> | I want to test if a file exists but my path contain a directory name that
> | differs from a server to another.
> | In shell i would have done something like that :
> | #!/b
smain...@free.fr wrote:
> I'm just beginning to learn python language and i'm trying to do something
> and i can't figure it out.
>
> I want to test if a file exists but my path contain a directory name that
> differs from a server to another.
> In shell i would have done something like that :
>
On 30Dec2010 09:36, smain...@free.fr wrote:
| I want to test if a file exists but my path contain a directory name that
| differs from a server to another.
| In shell i would have done something like that :
| #!/bin/bash
| mypath=/dire*/directory02/
| myfile=filename
| myfile=toto
| if [ -f $mypat
Hello,
2010/12/30 :
> How can i do the same thing (wildcard in a directory name) in python please ?
You can get the contents of a directory with os.listdir and filter
with fnmatch.fnmatch more or less as in the example from the
documentation:
-
import fnmatch
import os
for f
On Jul 1, 3:36 am, Duncan Booth <[EMAIL PROTECTED]> wrote:
> 7stud <[EMAIL PROTECTED]> wrote:
> > Here is a program to print out the files in a directory:
>
> > ---
> > import os
>
> > myfiles = os.listdir("../")
> > print myfiles
>
> > for afile in myfiles:
> > print afile
> > if o
7stud <[EMAIL PROTECTED]> wrote:
> Here is a program to print out the files in a directory:
>
> ---
> import os
>
> myfiles = os.listdir("../")
> print myfiles
>
> for afile in myfiles:
> print afile
> if os.path.isfile(afile):
> print afile, "___file"
> if os.path.i
[EMAIL PROTECTED] wrote:
> On Apr 7, 4:56 pm, "7stud" <[EMAIL PROTECTED]> wrote:
>> Here's the code:
>>
>> import os, os.path, pprint
>>
>> mydir = "/Users/me/2testing"
>>
>> files = [file for file in os.listdir(mydir)]
>> pprint.pprint(files)
>>
>> print os.path.join(mydir, "helloWorl
On Apr 7, 2:56 am, "7stud" <[EMAIL PROTECTED]> wrote:
> Here's the code:
>
> import os, os.path, pprint
>
> mydir = "/Users/me/2testing"
>
> files = [file for file in os.listdir(mydir)]
> pprint.pprint(files)
>
> print os.path.join(mydir, "helloWorld.py")
>
> files = [file
> for file i
On Apr 7, 4:56 pm, "7stud" <[EMAIL PROTECTED]> wrote:
> Here's the code:
>
> import os, os.path, pprint
>
> mydir = "/Users/me/2testing"
>
> files = [file for file in os.listdir(mydir)]
> pprint.pprint(files)
>
> print os.path.join(mydir, "helloWorld.py")
>
> files = [file
> for file i
On Apr 7, 6:56 pm, "7stud" <[EMAIL PROTECTED]> wrote:
> Here's the code:
>
> import os, os.path, pprint
>
> mydir = "/Users/me/2testing"
>
> files = [file for file in os.listdir(mydir)]
> pprint.pprint(files)
>
> print os.path.join(mydir, "helloWorld.py")
>
> files = [file
> for file i
7stud wrote:
> Here's the code:
>
> import os, os.path, pprint
>
> mydir = "/Users/me/2testing"
>
> files = [file for file in os.listdir(mydir)]
> pprint.pprint(files)
>
> print os.path.join(mydir, "helloWorld.py")
>
> files = [file
> for file in os.listdir(mydir)
> if os.path.isf
> Boudreau, Emile wrote:
(snip)
>> I have tried variations of: os.path.isfile( os.path.join("C:\\temp\\",
>> "rqp-win32-app", "*.tar.gz"))
As a side note, the whole point of os.path is to help writing portable
code. So passing an os.specific path componant is somewhat counter
productive !-)
(s
Boudreau, Emile wrote:
> Hello All,
> I'm new to Python and it looks like people that post here do get
> a good answer back so I figured I'd try my luck.
>
> I'm trying to check a directory to see if there is a file that has the
> name "startOfString" + some version number + "inst.tar.gz
Boudreau, Emile wrote:
> Hello All,
> I'm new to Python and it looks like people that post here do get
> a good answer back so I figured I'd try my luck.
>
> I'm trying to check a directory to see if there is a file that has the
> name "startOfString" + some version number + "inst.tar.gz
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