Re: Simple - looking for a way to do an element exists check..

On Sat, 23 Feb 2008 17:19:47 -0800, thebjorn wrote: > On Feb 23, 6:18 pm, Paul Hankin <[EMAIL PROTECTED]> wrote: > >> IMO Jason's solution of testing containment in a generator is better >> (more readable). >> if element[0] not in (x[0] for x in a): >> a.append(element) > > It may be

Re: Simple - looking for a way to do an element exists check..

On Feb 24, 2:24 am, Paul Rubin wrote: > thebjorn <[EMAIL PROTECTED]> writes: > > If the lists are long enough to care, either rewrite use a set-based > > solution if the items are hashable, or keep the elements sorted and > > rewrite to use the bisect module if the elemen

Re: Simple - looking for a way to do an element exists check..

thebjorn <[EMAIL PROTECTED]> writes: > If the lists are long enough to care, either rewrite use a set-based > solution if the items are hashable, or keep the elements sorted and > rewrite to use the bisect module if the elements can be ordered. Well, you want a tree data structure to have fast ins

Re: Simple - looking for a way to do an element exists check..

On Feb 23, 6:18 pm, Paul Hankin <[EMAIL PROTECTED]> wrote: > On Feb 22, 7:01 pm, Paul McGuire <[EMAIL PROTECTED]> wrote: > > > On Feb 22, 12:54 pm, Paul Rubin wrote: > > > > Paul Rubin writes: > > > > if any(x==element[0] for x in a): > > >

Re: Simple - looking for a way to do an element exists check..

On Feb 22, 7:01 pm, Paul McGuire <[EMAIL PROTECTED]> wrote: > On Feb 22, 12:54 pm, Paul Rubin wrote: > > > Paul Rubin writes: > > >     if any(x==element[0] for x in a): > > >       a.append(element) > > > Should say: > > >      if any(x[0]==ele

Re: Simple - looking for a way to do an element exists check..

TeroV wrote: > It isn't list comprehension, it is generator expression > http://en.wikipedia.org/wiki/Python_syntax_and_semantics#Generator_expressions Nice. :) -- http://mail.python.org/mailman/listinfo/python-list

Re: Simple - looking for a way to do an element exists check..

Boris Ozegovic wrote: > Paul Rubin wrote: > >> if any(x[0]==element[0] for x in a): > > How come this list comprehension isn't in [] brackets? It isn't list comprehension, it is generator expression http://en.wikipedia.org/wiki/Python_syntax_and_semantics#Generator_expressions -- Tero --

Re: Simple - looking for a way to do an element exists check..

Paul Rubin wrote: > if any(x[0]==element[0] for x in a): How come this list comprehension isn't in [] brackets? -- http://mail.python.org/mailman/listinfo/python-list

Re: Simple - looking for a way to do an element exists check..

Paul McGuire <[EMAIL PROTECTED]> writes: > I'm still getting used to 'any' and 'all' as new Python built-ins - > but they'll do the short-circuiting as well as a for-loop-with-break. > But I think a set- or dict-based solution will still surpass a list- > based one for the OP. I guess I don't unde

Re: Simple - looking for a way to do an element exists check..

On Feb 22, 3:38 pm, Paul Rubin wrote: > Paul McGuire <[EMAIL PROTECTED]> writes: > > I think you have this backwards.  Should be: > > >      if not any(x[0]==element[0] for x in a): > >         a.append(element) > > I think you are right, it was too early for me to be rea

Re: Simple - looking for a way to do an element exists check..

Paul McGuire <[EMAIL PROTECTED]> writes: > I think you have this backwards. Should be: > > if not any(x[0]==element[0] for x in a): > a.append(element) I think you are right, it was too early for me to be reading code when I posted that ;-) -- http://mail.python.org/mailman/listinf

Re: Simple - looking for a way to do an element exists check..

On Feb 22, 12:54 pm, Paul Rubin wrote: > Paul Rubin writes: > >     if any(x==element[0] for x in a): > >       a.append(element) > > Should say: > >      if any(x[0]==element[0] for x in a): >         a.append(element) I think you have this ba

Re: Simple - looking for a way to do an element exists check..

Paul Rubin writes: > if any(x==element[0] for x in a): > a.append(element) Should say: if any(x[0]==element[0] for x in a): a.append(element) -- http://mail.python.org/mailman/listinfo/python-list

Re: Simple - looking for a way to do an element exists check..

rh0dium <[EMAIL PROTECTED]> writes: > found = False > for item in a: > if item[0] == element[0] > found = True > break > if not found: > a.append(element) > > But this is just ugly - Is there a simpler way to interate over all > items in a without using a found flag? Untested and I'm

Re: Simple - looking for a way to do an element exists check..

On Feb 22, 10:20 am, rh0dium <[EMAIL PROTECTED]> wrote: > Hi all, > > I have a simple list to which I want to append another tuple if > element 0 is not found anywhere in the list. > > element = ('/smsc/chp/aztec/padlib/5VT.Cat', > '/smsc/chp/aztec/padlib', > '5VT.Cat', (33060)) > > element1 =

Re: Simple - looking for a way to do an element exists check..

On Feb 22, 11:20 am, rh0dium <[EMAIL PROTECTED]> wrote: > Hi all, > > I have a simple list to which I want to append another tuple if > element 0 is not found anywhere in the list. > > element =  ('/smsc/chp/aztec/padlib/5VT.Cat', >   '/smsc/chp/aztec/padlib', >   '5VT.Cat', (33060)) > > element1 =

Re: Simple - looking for a way to do an element exists check..

On Feb 22, 11:20 am, rh0dium <[EMAIL PROTECTED]> wrote: > > found = False > for item in a: >   if item[0] == element[0] >     found = True >     break > if not found: >   a.append(element) > > But this is just ugly - Is there a simpler way to interate over all > items in a without using a found fla