On Feb 22, 10:20 am, rh0dium <[EMAIL PROTECTED]> wrote:
> Hi all,
>
> I have a simple list to which I want to append another tuple if
> element 0 is not found anywhere in the list.
>
> element = ('/smsc/chp/aztec/padlib/5VT.Cat',
> '/smsc/chp/aztec/padlib',
> '5VT.Cat', (33060))
>
> element1 = ('/smsc/chp/aztec/padlib/5VT.Cat2',
> '/smsc/chp/aztec/padlib',
> '5VT.Cat2', (33060))
>
> a = [ ('/smsc/chp/aztec/padlib/5VT.Cat',
> '/smsc/chp/aztec/padlib',
> '5VT.Cat', (33060)),
> ('/smsc/chp/aztec/padlib/padlib.TopCat%',
> '/smsc/chp/aztec/padlib',
> 'padlib.TopCat%', (33204)),
> ('/smsc/chp/aztec/padlib/Regulators.Cat%',
> '/smsc/chp/aztec/padlib',
> 'Regulators.Cat%', (33204))]
>
> So my code would look something like this.
>
> found = False
> for item in a:
> if item[0] == element[0]
> found = True
> break
> if not found:
> a.append(element)
>
> But this is just ugly - Is there a simpler way to interate over all
> items in a without using a found flag?
>
> Thanks
How-about using a generator expression and Python's built-in "in"
operator:
>>> def example(myData, newData):
... if newData[0] not in (x[0] for x in myData):
... myData.append( newData )
...
>>> l = []
>>> example( l, ('a', 'apple', 'aviary') )
>>> l
[('a', 'apple', 'aviary')]
>>> example( l, ('s', 'spam', 'silly') )
>>> l
[('a', 'apple', 'aviary'), ('s', 'spam', 'silly')]
>>> example( l, ('s', 'suck-tastic') )
>>> l
[('a', 'apple', 'aviary'), ('s', 'spam', 'silly')]
>>>
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