Re: Prepending string "@" to usernames

2013-05-24 Thread Larry Hudson
On 05/24/2013 03:53 PM, Thomas Murphy wrote: Here's where I got to: raw_address = "cookielover93 TheGermanHatesSaurkraut WhatsThatBoy932834" address_library = [raw_address.split()] print address_library for address in address_library: final_address = "@" + str(address) print final_addr

Re: Prepending string "@" to usernames

2013-05-24 Thread Thomas Murphy
> Which can be tidily written as a list comprehension: > > final_address = ['@' + address for address in raw_address.split()] > > -tkc > > Ah! Thanks Tim…that tidiness is something I'm trying to head towards in my own code. I'm trying to transition from the need to visually write every little ste

Re: Prepending string "@" to usernames

2013-05-24 Thread Tim Chase
On 2013-05-24 19:04, Thomas Murphy wrote: >> raw_address = "cookielover93 TheGermanHatesSaurkraut >> WhatsThatBoy932834" address_library = raw_address.split() >> print address_library >> >> final_address = [] >> for address in address_library: >> final_address.append("@" + str(address)) >> prin

Re: Prepending string "@" to usernames

2013-05-24 Thread Mark Lawrence
On 25/05/2013 00:04, Thomas Murphy wrote: Maybe this is what you're looking for? raw_address = "cookielover93 TheGermanHatesSaurkraut WhatsThatBoy932834" address_library = raw_address.split() print address_library final_address = [] for address in address_library: final_address.append("@"

Re: Prepending string "@" to usernames

2013-05-24 Thread Andrew Berg
On 2013.05.24 17:53, Thomas Murphy wrote: > I know I'm iterating wrong. May I ask how? .split() already returns a list, so instead of iterating over the list and getting a single username, you iterate over the list and get a single list. -- CPython 3.3.2 | Windows NT 6.2.9200 / FreeBSD 9.1 -- ht

Re: Prepending string "@" to usernames

2013-05-24 Thread Thomas Murphy
> Maybe this is what you're looking for? > > raw_address = "cookielover93 TheGermanHatesSaurkraut WhatsThatBoy932834" > address_library = raw_address.split() > print address_library > > final_address = [] > for address in address_library: > final_address.append("@" + str(address)) > print final

Re: Prepending string "@" to usernames

2013-05-24 Thread Dan Stromberg
On Fri, May 24, 2013 at 3:53 PM, Thomas Murphy wrote: > Hi beloved list, > > I'm having a dumb and SO doesn't seem to have this one answered. I was > sent a long list of instagram usernames to tag for a nightlife > announcement in this format(not real names(i hope)) > > cookielover93 > TheGermanHa