Paul Rubin wrote:
> Ron Adam <[EMAIL PROTECTED]> writes:
>
>>>A new statement is proposed with the syntax:
>>>with EXPR as VAR:
>>>BLOCK
>>>Here, 'with' and 'as' are new keywords; EXPR is an arbitrary
>>>expression (but not an expression-list)...
>>
>>How is EXPR arbitr
Ron Adam <[EMAIL PROTECTED]> writes:
> > A new statement is proposed with the syntax:
> > with EXPR as VAR:
> > BLOCK
> > Here, 'with' and 'as' are new keywords; EXPR is an arbitrary
> > expression (but not an expression-list)...
>
> How is EXPR arbitrary? Doesn't it n
