Ron Adam <[EMAIL PROTECTED]> writes: > > A new statement is proposed with the syntax: > > with EXPR as VAR: > > BLOCK > > Here, 'with' and 'as' are new keywords; EXPR is an arbitrary > > expression (but not an expression-list)... > > How is EXPR arbitrary? Doesn't it need to be or return an object that > the 'with' statement can use? (a "with" object with an __enter__ and > __exit__ method?)
That's not a syntactic issue. "x / y" is a syntactically valid expression even though y==0 results in in a runtime error. -- http://mail.python.org/mailman/listinfo/python-list
