Il Thu, 02 Apr 2009 13:44:38 +, Sion Arrowsmith ha scritto:
> mattia wrote:
>> So, I'm looking for a way to "reset" the next() value every
>>time i complete the scan of a list.
>
> itertools.cycle ?
Perfect, thanks.
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mattia wrote:
> So, I'm looking for a way to "reset" the next() value every
>time i complete the scan of a list.
itertools.cycle ?
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under construction
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Il Sun, 29 Mar 2009 12:00:38 -0400, andrew cooke ha scritto:
> mattia wrote:
>>[i wrote]:
>>> don't you just want to have a new job machine?
>>>
>>> for job_list in job_list_list:
>>> job_machine = dict((x+1, iter(JOBS[x])) for x in range(NJOBS)) for x
>>> in job_list:
>>> print(next(job_m
mattia wrote:
>[i wrote]:
>> don't you just want to have a new job machine?
>>
>> for job_list in job_list_list:
>> job_machine = dict((x+1, iter(JOBS[x])) for x in range(NJOBS)) for x
>> in job_list:
>> print(next(job_machine[x]))
ok - btw you can probably simplify the code.
this might w
Il Sun, 29 Mar 2009 11:17:50 -0400, andrew cooke ha scritto:
> mattia wrote:
>> Hi all, I a list of jobs and each job has to be processed in a
>> particular order by a list of machines.
>> A simple representation is:
>> # Ordering of machines
>> JOB1 = [3, 1, 2, 4]
>> JOB2 = [2, 3, 1, 4]
>> JOBS =
mattia wrote:
> Hi all, I a list of jobs and each job has to be processed in a particular
> order by a list of machines.
> A simple representation is:
> # Ordering of machines
> JOB1 = [3, 1, 2, 4]
> JOB2 = [2, 3, 1, 4]
> JOBS = [JOB1, JOB2]
> NJOBS = len(JOBS)
> Now, I have a list of jobs and I wa
