Il Sun, 29 Mar 2009 12:00:38 -0400, andrew cooke ha scritto: > mattia wrote: >>[i wrote]: >>> don't you just want to have a new job machine? >>> >>> for job_list in job_list_list: >>> job_machine = dict((x+1, iter(JOBS[x])) for x in range(NJOBS)) for x >>> in job_list: >>> print(next(job_machine[x])) > > ok - btw you can probably simplify the code. > > this might work: > > job_machine = list(map(iter, JOBS)) > > andrew > > [...] >> Well, you are right, just creating every time a new dict is a good >> solution, I was just adding complexity to a simple problem, thanks.
Yes, it works perfectly, the only change is next(job_machine[x-1]). Thanks. -- http://mail.python.org/mailman/listinfo/python-list
