wswilson a écrit :
> Here is my code:
>
> listing = {'id': ['a', 'b', 'c'], 'name': ['Joe', 'Jane', 'Bob']}
>
> I need to output:
>
> id name
> a Joe
> b Jane
> c Bob
>
> I could do:
>
> print 'id', 'name'
> for id, name in zip(listing['id'], listing['name']): print id, name
>
> but that only
> -Original Message-
> From: [EMAIL PROTECTED]
[mailto:python-
> [EMAIL PROTECTED] On Behalf Of wswilson
> Sent: Wednesday, April 18, 2007 1:39 PM
> To: python-list@python.org
> Subject: Iterate through a dictionary of lists one "line" at a time
>
> He
On Apr 18, 2:54 pm, Arnaud Delobelle <[EMAIL PROTECTED]> wrote:
> On Apr 18, 7:39 pm, wswilson <[EMAIL PROTECTED]> wrote:
>
>
>
> > Here is my code:
>
> > listing = {'id': ['a', 'b', 'c'], 'name': ['Joe', 'Jane', 'Bob']}
>
> > I need to output:
>
> > id name
> > a Joe
> > b Jane
> > c Bob
>
> > I c
wswilson wrote:
> Here is my code:
>
> listing = {'id': ['a', 'b', 'c'], 'name': ['Joe', 'Jane', 'Bob']}
>
> I need to output:
>
> id name
> a Joe
> b Jane
> c Bob
>
> I could do:
>
> print 'id', 'name'
> for id, name in zip(listing['id'], listing['name']): print id, name
>
> but that only wo
On Apr 18, 7:39 pm, wswilson <[EMAIL PROTECTED]> wrote:
> Here is my code:
>
> listing = {'id': ['a', 'b', 'c'], 'name': ['Joe', 'Jane', 'Bob']}
>
> I need to output:
>
> id name
> a Joe
> b Jane
> c Bob
>
> I could do:
>
> print 'id', 'name'
> for id, name in zip(listing['id'], listing['name']): p
Here is my code:
listing = {'id': ['a', 'b', 'c'], 'name': ['Joe', 'Jane', 'Bob']}
I need to output:
id name
a Joe
b Jane
c Bob
I could do:
print 'id', 'name'
for id, name in zip(listing['id'], listing['name']): print id, name
but that only works if there are two entries in the dictionary, id
