wswilson a écrit :
> Here is my code:
>
> listing = {'id': ['a', 'b', 'c'], 'name': ['Joe', 'Jane', 'Bob']}
>
> I need to output:
>
> id name
> a Joe
> b Jane
> c Bob
>
> I could do:
>
> print 'id', 'name'
> for id, name in zip(listing['id'], listing['name']): print id, name
>
> but that only works if there are two entries in the dictionary, id and
> name, and I know what they are. My problem is I don't know how many of
> these entries there will be. Thanks for any help you can give!
>
The most simple and generic I see, it could be even more simple if you
don't care of memory usage :
Let's fill a random dict :
In [118]: d=dict(zip((str(e) for e in xrange(10)), ([i**e for e in
xrange(5)] for i in xrange(10))))
In [119]: d
Out[119]:
{'0': [1, 0, 0, 0, 0],
'1': [1, 1, 1, 1, 1],
'2': [1, 2, 4, 8, 16],
'3': [1, 3, 9, 27, 81],
'4': [1, 4, 16, 64, 256],
'5': [1, 5, 25, 125, 625],
'6': [1, 6, 36, 216, 1296],
'7': [1, 7, 49, 343, 2401],
'8': [1, 8, 64, 512, 4096],
'9': [1, 9, 81, 729, 6561]}
go on :
In [146]: sorted_keys = tuple(sorted(d.keys()))
In [147]: from itertools import izip, chain
In [148]: sorted_keys = tuple(sorted(d.keys()))
In [149]: sorted_values = ( d[k] for k in sorted_keys )
In [150]: for vals in chain([sorted_keys], izip(*sorted_values)) :
.....: print '%5s'*len(d) % vals
.....:
.....:
0 1 2 3 4 5 6 7 8 9
1 1 1 1 1 1 1 1 1 1
0 1 2 3 4 5 6 7 8 9
0 1 4 9 16 25 36 49 64 81
0 1 8 27 64 125 216 343 512 729
0 1 16 81 256 625 1296 2401 4096 6561
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