On 10/8/17 1:00 AM, Andrew Z wrote:
and how about adding "IF" into the mix ?
as in :
a=0
dict= {10: ['a',1,'c'], 20: ['d',2,'f']}
for i in dict:
p+= 10 if dict[i][1] in [1,2,3,4,5] else 0
can i "squish" "for" and "if" together ? or will it be too perl-ish ?
sum(10 for v in dict.val
and how about adding "IF" into the mix ?
as in :
a=0
dict= {10: ['a',1,'c'], 20: ['d',2,'f']}
for i in dict:
p+= 10 if dict[i][1] in [1,2,3,4,5] else 0
can i "squish" "for" and "if" together ? or will it be too perl-ish ?
On Sun, Oct 8, 2017 at 12:37 AM, Andrew Z wrote:
> Nathan, Bob
Nathan, Bob - on the money. Thank you !
On Sat, Oct 7, 2017 at 11:30 PM, bob gailer wrote:
> On 10/7/2017 11:17 PM, Nathan Hilterbrand wrote:
>
>> dict= {10: ['a',1,'c'], 20: ['d',2,'f']}
>> p = sum([dict[i][1] for i in dict])
>>
>> Something like that?
>>
> Ah, but that's 2 lines.
>
> sum(val[1
On 10/7/2017 11:17 PM, Nathan Hilterbrand wrote:
dict= {10: ['a',1,'c'], 20: ['d',2,'f']}
p = sum([dict[i][1] for i in dict])
Something like that?
Ah, but that's 2 lines.
sum(val[1] for val in {10: ['a',1,'c'], 20: ['d',2,'f']}.values())
On Sat, Oct 7, 2017 at 11:07 PM, Andrew Z wrote:
He
dict= {10: ['a',1,'c'], 20: ['d',2,'f']}
p = sum([dict[i][1] for i in dict])
Something like that?
On Sat, Oct 7, 2017 at 11:07 PM, Andrew Z wrote:
> Hello,
> i wonder how can i accomplish the following as a one liner:
>
> dict= {10: ['a',1,'c'], 20: ['d',2,'f']}
> p = 0
> for i in dict:
>
Hello,
i wonder how can i accomplish the following as a one liner:
dict= {10: ['a',1,'c'], 20: ['d',2,'f']}
p = 0
for i in dict:
p += dict[i][1]
Thank you
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