> Actually, the code in the book is:
>
> def f1():
> x = 88
> f2(x)
>
> def f2(x):
> print x
>
> f1()
>
> which makes all the difference in the world. Not to mention that this
> particular section of the book is giving an example of how to write the
> code *without* using nested fun
Thanks for the answers.
I do understand (and verified) that if I define f2 within f1, it works
as expected. But in the "learning pyton 2nd edition" at page 205 it is
said that "Programs are much simpler if you do not nest defs within
defs" (juste before the code mentioned in my initial message).
I have a problem understanding the scope of variable in nested
function. I think I got it nailed to the following example copied from
Learning Python 2nd edition page 205. Here is the code.
def f1() :
x=88
f2()
def f2() :
print 'x=',x
f1()
that returns an error saying that "NameError:
Scott David Daniels wrote:
> biner wrote:
> > I am using a program that has to read binary data from files
coming
> > from different machines. The file are always written with big
endian.
>
> Diez B. Roggisch wrote:
> [Scott David Daniels wrote]
> >>How about sys.byteorder?
> > This doesn't h
