Hi All,
Please ignore it, I was able to figure out it.
for dev in devlist:
print (dev.name, dev.id)
--
Thanks & Regards
Mohan L
On Fri, Sep 27, 2019 at 8:41 PM Mohan L wrote:
> Hi All,
>
> I am using get_devices_list method from this module:
> https://github.com/
:
devicename1 10
devicename2 11
devicename3 12
I spend quit some time still not able to figure out how to parse. Can some
one through some light on how to phrase it.
--
Thanks & Regards
Mohan L
--
https://mail.python.org/mailman/listinfo/python-list
Hi All,
I am using the bellow script to watch directories. Using 20 seconds to
aggregate together a larger chunk of events and enabled coalescing of
events.
I wanted to send an email notification with content of logfile after 15
mins on any change. The idea is I want to send only one mail for ch
On Fri, Oct 4, 2013 at 12:14 AM, MRAB wrote:
> On 03/10/2013 17:11, Mohan L wrote:
>
>> Dear All,
>>
>> I have two list of dictionaries like below:
>>
>> In the below dictionaries the value of ip can be either hostname or ip
>> address.
>>
&
me': 'hostname8', 'ip_addr': ''},
{'hostname': 'hostname200', 'ip_addr': 'xxx.xx.xxx.200'},
{'hostname': 'hostname300', 'ip_addr': 'xxx.xx.xxx.400'},
)
trying to get the following difference from the above dictionary
1). compare the value of 'ip' in output1 dictionary with either 'hostname'
and 'ip_addr' output2 dictionary and print their intersection. Tried below
code:
for doc in output1:
for row in output2:
if((row["hostname"] == doc["ip"]) or (row["ip_addr"] ==
doc["ip"])):
print doc["ip"],doc["count"]
*output:*
hostname1 212
hostname2 27
hostname10 1
hostname8 2
xxx.xx.xxx.11 3
xxx.xx.xxx.12 90
xxx.xx.xxx.13 12
xxx.xx.xxx.14 21
xxx.xx.xxx.15 54
xxx.xx.xxx.16 34
2). need to print the below output if the value of 'ip' in output1
dictionary is not there in in output2 dictionary(ip/hostname which is there
in output1 and not there in output2):
xxx.xx.xxx.1 3
xxx.xx.xxx.2 4
xxx.xx.xxx.3 8
xxx.xx.xxx.4 10
hostname3 513
hostname4 98
xxx.xx.xxx.17 11
xxx.xx.xxx.18 2
xxx.xx.xxx.19 19
xxx.xx.xxx.20 21
xxx.xx.xxx.21 25
xxx.xx.xxx.22 31
xxx.xx.xxx.23 43
xxx.xx.xxx.24 46
xxx.xx.xxx.25 80
xxx.xx.xxx.26 91
xxx.xx.xxx.27 90
xxx.xx.xxx.28 10
xxx.xx.xxx.29 3
3). Ip address with is there only in output2 dictionary.
xxx.xx.xxx.200
xxx.xx.xxx.400
Any help would be really appreciated. Thank you
Thanks
Mohan L
--
https://mail.python.org/mailman/listinfo/python-list
On Tue, Jul 16, 2013 at 2:12 PM, Joshua Landau wrote:
> On 16 July 2013 07:55, Mohan L wrote:
> >
> > Dear All,
> >
> > Here is my script :
> >
> > #!/usr/bin/python
> > import re
> >
> > # A string.
> > logs = "dat
27;}
need help to correct the below regex
(?P(date=(?P[^\s]+))\s+(time=(?P[^\s]+)))"
so that It will have : 'datetime': '2012-11-28 21:14:59' instead of
'datetime': 'date=2012-11-28 time=21:14:59'
any help would be greatly appreciated
Thanks
Mohan L
--
http://mail.python.org/mailman/listinfo/python-list
