On Friday, September 21, 2012 2:22:08 PM UTC+8, Cosmia Luna wrote:
> I'm porting my code to python3, and found there is no parse_http_list in any
> module of urllib of python3.
>
>
>
> So, is there a public API equvalent for urllib2.parse_http_
I'm porting my code to python3, and found there is no parse_http_list in any
module of urllib of python3.
So, is there a public API equvalent for urllib2.parse_http_list?
Thanks.
Cosmia Luna
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I think I got the way to handle it but with small problem and probably at
unnecessary performance cost. If you're going to use it, be sure rewrite the
code and remove the lines which you don't need. Ad, test them, the code
below is only tested on py3.2, and may contains a lot of bugs even in py
On Saturday, March 17, 2012 6:04:58 PM UTC+8, Cosmia Luna wrote:
> On Saturday, March 17, 2012 5:25:06 PM UTC+8, Peter Otten wrote:
> > Cosmia Luna wrote:
> >
> > > I'm porting my existing work to Python 3.X, but...
> > >
> > > class F
On Saturday, March 17, 2012 5:25:06 PM UTC+8, Peter Otten wrote:
> Cosmia Luna wrote:
>
> > I'm porting my existing work to Python 3.X, but...
> >
> > class Foo:
> > def bar(self):
> > pass
> >
> > mthd = Foo.bar
> >
&
On Saturday, March 17, 2012 3:34:57 PM UTC+8, Richard Thomas wrote:
> On Saturday, 17 March 2012 05:30:34 UTC, Cosmia Luna wrote:
> > I'm porting my existing work to Python 3.X, but...
> >
> > class Foo:
> > def bar(self):
> > pass
&
I'm porting my existing work to Python 3.X, but...
class Foo:
def bar(self):
pass
mthd = Foo.bar
assert mthd.im_class is Foo # this does not work in py3k
So, how can I get a reference to Foo? This is important when writing
decorators, the only way I can think out is:
class Foo:
class Foo(object):
def bar(self):
return 'Something'
func = Foo().bar
if type(func) == : # This should be always true
pass # do something here
What should type at ?
Thanks
Cosmia
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On Sunday, March 11, 2012 4:16:52 AM UTC+8, Christian Heimes wrote:
> Am 10.03.2012 20:33, schrieb Cosmia Luna:
> > I'm not searching for a full solution and only want to know how to use
> > hashlib to create a equivalent string like
>
> If you chance your mind and cho
I'm not searching for a full solution and only want to know how to use hashlib
to create a equivalent string like
crypt.crypt('123456', '$6$ds41p/9VMA.BHH0U') returns the string below.
'$6$ds41p/9VMA.BHH0U$yv25s7jLxTRKLDNjIvT0Qc2jbcqdFRi5.PftO3cveTvjK49JhwCarIowOfrrNPD/PpYT3n6oNDIbjAONh8RXt1'
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