On Sunday, March 11, 2012 4:16:52 AM UTC+8, Christian Heimes wrote: > Am 10.03.2012 20:33, schrieb Cosmia Luna: > > I'm not searching for a full solution and only want to know how to use > > hashlib to create a equivalent string like > > If you chance your mind and choose to use a full solution, then I highly > recommend passlib [1]. It has an implementation of SHA-512 crypt as > indicated by the number 6 in the header of your string. > > By the way "$6$ds41p/9VMA.BHH0U" is *not* the salt. Just > "ds41p/9VMA.BHH0U" is the salt, 6 is a hash identifier. > > Christian > > [1] http://packages.python.org/passlib/
PassLib works for me. What I want is passlib.context, I need it in consideration of forward compatibility. Thanks a lot. But I still want to know how it is implemented, I read passlib's source but I found he/she re-implemented hashlib, which I can't understand. Now I knows that the encoding is hash64 instead of base64, but I can't know that. PassLib is too difficult for me. Anyone knows the accurate process? Cosmia -- http://mail.python.org/mailman/listinfo/python-list
