On Wed, Sep 2, 2020 at 11:22 AM David Raymond wrote:
>
> Would it be something as simple as:
>
> rows.sort(key = lambda x: (x[0], x[3], x[4], sort_list.index(x[6])))
This is perfect - thanks!
> -Original Message-
> From: Python-list
> On Behalf Of Larry Martell
> Sent: Wednesday, Sept
Peter Otten wrote:
> group_key = itemgetter(0, 3, 4)
>
>
> def sort_key(row, lookup={k: i for i, k in enumerate(sort_list)}):
> return lookup[row[6]]
>
>
> result = list(
> chain.from_iterable(
> sorted(group, key=sort_key)
> for _key, group in groupby(rows, key=group_k
Larry Martell wrote:
> I have a list of tuples, and I want to group them by 3 items (0, 3, 4)
> and then within each group sort the data by a 4th item (6) using a
> sort order from another list. The list is always ordered by the 3
> grouping items.
>From your description I deduced
from itertools
Would it be something as simple as:
rows.sort(key = lambda x: (x[0], x[3], x[4], sort_list.index(x[6])))
-Original Message-
From: Python-list On
Behalf Of Larry Martell
Sent: Wednesday, September 2, 2020 1:55 PM
To: Python
Subject: grouping and sorting within groups using another lis
I have a list of tuples, and I want to group them by 3 items (0, 3, 4)
and then within each group sort the data by a 4th item (6) using a
sort order from another list. The list is always ordered by the 3
grouping items.
For example, if I have this list:
rows =
[('a', 'b', 'c', 'd', 'e', 'f', 'blue
