* Richard Lynch <[EMAIL PROTECTED]>:
>
> > '$shippingCountry1')")))
> > {
> >echo "the insertiont cannot be done";
>
> echo mysql_error();
>
> http://php.net/mysql_error
>
> >exit();
> > }
> > header("Location:http://$HTTP_HOST/$DOCROOT/allright.html";);
>
> DON'T DO THAT!!!
>
> Just
> '$shippingCountry1')")))
> {
>echo "the insertiont cannot be done";
echo mysql_error();
http://php.net/mysql_error
>exit();
> }
> header("Location:http://$HTTP_HOST/$DOCROOT/allright.html";);
DON'T DO THAT!!!
Just do:
include 'allright.html';
The Location header is for a docu
Hi!
Thank you for the reply!
I have change the function:
function doReg($fname1="",$family1="",$company1="", $MOL1="", $dannum1="",
$bulstat1="", $phone1="", $email1="", $username1="", $password1="",
$payment1="",
$maillist1="", $Addr1="", $City1="", $zipcode1="", $Country1="",
$shippingName1=""
Are you getting an error? If so what does it say. Also in your code you
have nothing to tell you if something is going wrong. Use echo
statements - say something if the connection or the query doesn't go
through. Also noticed that when you made the connection to the DB you
didn't assign it t
> I'm having a problem with a php application;
>
> I have two files: one is ccadduser wich adds users to a controlcenter
> that I am currently designing for a website.
>
> In that ccaduserfile I call for a function checkpermission(); this
> function is defined in another file called ccfunctions
>
>
-Original Message-
From: Vincent Jansen [mailto:[EMAIL PROTECTED]
Sent: 13 January 2004 13:05
To: 'Dave Carrera'; 'Richard Davey'
Cc: [EMAIL PROTECTED]
Subject: RE: [PHP] Function Problem (Long-ish)
I doubt that...
MySQL says:
Mixing of GROUP columns (MIN(),MAX(),COUNT()...) w
y'
Cc: [EMAIL PROTECTED]
Subject: RE: [PHP] Function Problem (Long-ish)
Thanks for the reply Richard.
If I use this sql in my func:
$sql = mysql_query("select count(fieldtocount) as cnt, sum(fieldforsum)
as total from $tab3 where fieldtocompare =\"$varcomparedwith\"");
I am puzzled why and if you or the list can help I would appreciate it.
Thank you
Dave C
-Original Message-
From: Richard Davey [mailto:[EMAIL PROTECTED]
Sent: 13 January 2004 12:48
To: Dave Carrera
Cc: [EMAIL PROTECTED]
Subject: Re: [PHP] Function Problem (Long-ish)
Hello Dave,
Tue
On Tuesday 13 January 2004 20:34, Dave Carrera wrote:
[snip]
> My Question is Why ?
>
> Any help is a appreciated and I thank you fully in advance.
You're not checking for errors. Incorporate error checking code and make use
of mysql_error().
--
Jason Wong -> Gremlins Associates -> www.gremli
From: "Dave Carrera" <[EMAIL PROTECTED]>
> I get a Warning:
> mysql_fetch_array(): supplied argument is not a valid MySQL result
resource
Whenever you get this warning it's because your query failed for some reason
and you're trying to use a result that's not valid. Use mysql_error() to
see wha
Hello Dave,
Tuesday, January 13, 2004, 12:34:33 PM, you wrote:
DC> sql = mysql_query("select *, count(id) as cnt from table where
DC> somefield=\"somevar\""){
It's nothing to do with your function, simply that your SQL is invalid.
--
Best regards,
Richardmailto:[E
[snip]
Not sure why the last section won't work...
...so much code it made my head hurt
[/snip]
Not sure either. Did you have a question?
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--- Frank Tudor <[EMAIL PROTECTED]> wrote:
> function $payment{
You probably mean payment, not $payment.
> header ("location:test_page.html");
The Location header has an uppercase L, a space after the colon, and an
absolute URL after the space. Your example violates all three.
Hope that helps.
Make that:
function payment{
global $payment;
-Gregory
-Original Message-
From: Gregory Kornblum [mailto:[EMAIL PROTECTED]
Sent: Monday, October 27, 2003 1:30 PM
To: 'Frank Tudor'; 1PHP
Subject: RE: [PHP] function problem (simple redirect)
>function $payment{
C
>function $payment{
Change that to:
function payment{
$global $payment;
Regards,
-Gregory
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To unsubscribe, visit: http://www.php.net/unsub.php
On 2003.02.15 00:11 Peter Gumbrell wrote:
[...]
$option_block .= "
[...]
Are you sure it's a scope problem ?
You haven't instantiated any $option_block variable when the loop
starts, so you're concatenating a string to a bunch of uninitialized
memory :)
I can't run your script at the moment, so
Friday, February 14, 2003 6:41 PM
To: Php-General
Subject: Re: [PHP] function problem
Exactly where does $option_block get put into $string?
-Kevin
- Original Message -
From: "Peter Gumbrell" <[EMAIL PROTECTED]>
To: "Php-General" <[EMAIL PROTECTED]>
Sent: Fri
Exactly where does $option_block get put into $string?
-Kevin
- Original Message -
From: "Peter Gumbrell" <[EMAIL PROTECTED]>
To: "Php-General" <[EMAIL PROTECTED]>
Sent: Friday, February 14, 2003 4:11 PM
Subject: [PHP] function problem
> I have a function below which populates a select l
Hey,
Of course they do, they work if I put the echo in the function its self, but
I dont need the echo in the function.
- Lee
"Marco Tabini" <[EMAIL PROTECTED]> wrote in message
news:1036911387.23753.1054.camel@;localhost.localdomain...
> Either add
>
> global $db;
>
> as the first line of the fu
Either add
global $db;
as the first line of the function or change your function call to:
$db = db_conn("$host","$user","$pass","$dab");
I assume that $host, $user, $pass and $dab actually contain some correct
values.
Marco
--
php|architect - The magazine for PHP Professionals
T
Try require_once($your_file) or verify in $your_file use the function
function_exists()
[]'s
Frederico Augusto Costa
[EMAIL PROTECTED]
On Wed, 7 Feb 2001, Miguel Loureiro wrote:
> Hello
> I have a script that use other script file(php) twice, I c
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