Exactly where does $option_block get put into $string?
-Kevin
----- Original Message -----
From: "Peter Gumbrell" <[EMAIL PROTECTED]>
To: "Php-General" <[EMAIL PROTECTED]>
Sent: Friday, February 14, 2003 4:11 PM
Subject: [PHP] function problem
> I have a function below which populates a select list, based on the query
> string and the field name. It then prints a string:
>
> function populate_selects($query_name, $db_field, $link, $string)
> {
> $result = mysql_query($query_name, $link) or die ("Could not execute
> query.");
> while ($columns = mysql_fetch_array($result))
> {
> $column = $columns[$db_field];
> global $option_block;
> $option_block .= "<OPTION name='vendor1'
> value=\"$column\">$column</OPTION>\n";
> }
> print $string;
> }
>
> Part of the string that is printed in $string is the $option_block which
is
> in the function. There seems to be some problem with scope here. I made
the
> $option_block variable global but it still won't print. I have tested that
> the $column field is being populated and it is, so I believe that it must
be
> the $option_block part that isn't working. Does anyone have any
suggestions?
>
> Peter Gumbrell
> [EMAIL PROTECTED]
>
>
>
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