.com]
Sent: Tuesday, July 05, 2011 5:47 PM
To: Robert Cummings
Cc: Dajka Tamás; php-general@lists.php.net
Subject: Re: [PHP] Foreach question
Just use count($arr) in your for-header, as it get's executed again
for each loop.
1), array('id'=>2))
On 11-07-05 11:46 AM, Louis Huppenbauer wrote:
Just use count($arr) in your for-header, as it get's executed again
for each loop.
1), array('id'=>2));
for($i=0;$i $arr[$i]['id']+1);
}
}
?>
Ok, so the extents are being updated on each pass of the loop :)
Ch
Just use count($arr) in your for-header, as it get's executed again
for each loop.
1), array('id'=>2));
for($i=0;$i $arr[$i]['id']+1);
}
}
?>
2011/7/5 Robert Cummings :
> On 11-07-05 10:48 AM, Dajka Tamás wrote:
>>
>> Thanks, that was interesting :) I think I got o
On Tue, Jul 5, 2011 at 2:40 PM, Dajka Tamas wrote:
> I've bumped into an interesting thing with foreach. I really don't know, if
> this is normal working, or why it is, so I got curious.
>
> The script:
>
> foreach ( $cats as &$c ) {
> echo $c['id'];
> if ( $c['id'] <
On 11-07-05 10:48 AM, Dajka Tamás wrote:
Thanks, that was interesting :) I think I got one step further in understanding
PHP :)
BTW, I've changed the loop to 'for' and it's working well :)
Can you show us your for loop? I'm not immediately sure how you use a
for loop to traverse a growing nu
On 11-07-05 09:40 AM, Dajka Tamas wrote:
foreach ( $cats as&$c ) {
echo $c['id'];
if ( $c['id']< 5 ) {
$c['id']++;
$cats[] = $c;
}
}
Given that you seem to want the above functi
Dajka Tamás
Cc: php-general@lists.php.net
Subject: Re: [PHP] Foreach question
On 11-07-05 10:39 AM, Dajka Tamás wrote:
> Ok, but if it would be that way I shouldn't get '122334455' for second
> output, no? The item count increments with every iteration of the loop.
>
> Or yo
On 11-07-05 10:39 AM, Dajka Tamás wrote:
Ok, but if it would be that way I shouldn't get '122334455' for second output,
no? The item count increments with every iteration of the loop.
Or you're saying that, it checks for an existance of nextitem before every
loop, and that will fail with just
On 11-07-05 10:39 AM, Dajka Tamás wrote:
Ok, but if it would be that way I shouldn't get '122334455' for second output,
no? The item count increments with every iteration of the loop.
Or you're saying that, it checks for an existance of nextitem before every
loop, and that will fail with jus
l always return true
with two elements? ( since the first elements copy is pushed as third element,
etc )
-Original Message-
From: Robert Cummings [mailto:rob...@interjinn.com]
Sent: Tuesday, July 05, 2011 4:28 PM
To: Dajka Tamás
Cc: php-general@lists.php.net
Subject: Re: [PHP] Foreach q
I don't think that it does this:
if ( count($elements) == 1 ) then loop 1;
else loop normally;
It's probably more something like that:
$i=count($elements);
loop:
$i--;
if($i == 0)
$last_loop = true;
else
$last_loop = false
if($last_loop)
exit;
else
goto loop;
But aside from tha
On 11-07-05 10:20 AM, Dajka Tamás wrote:
Hi,
Yeah, I'm really want to do that, since I'm working with the elements of the
original array ( skipped that part in sample code ).
I've tried your suggestion, but it gives the same result, so on just one input
is just gives back '1'.
Ahhh... you w
= $c;
}
}
But this is 'while' and it pops all elements from the array...
Cheers,
Tamas
-Original Message-
From: Louis Huppenbauer [mailto:louis.huppenba...@gmail.com]
Sent: Tuesday, July 05, 2011 4:12 PM
To: Robert Cummings
Cc: Dajka Tamas; php-general@lists.p
e same with each case )
Cheers,
Tamas
-Original Message-
From: Robert Cummings [mailto:rob...@interjinn.com]
Sent: Tuesday, July 05, 2011 4:06 PM
To: Dajka Tamas
Cc: php-general@lists.php.net
Subject: Re: [PHP] Foreach question
On 11-07-05 09:40 AM, Dajka Tamas wrote:
> Hi a
Or maybe he tried to do the following?
($c['id'] + 1));
}
}
?>
2011/7/5 Robert Cummings :
>
> On 11-07-05 09:40 AM, Dajka Tamas wrote:
>>
>> Hi all,
>>
>>
>>
>> I've bumped into an interesting thing with foreach. I really don't know,
>> if
>> this is normal working, or why it is,
On 11-07-05 09:40 AM, Dajka Tamas wrote:
Hi all,
I've bumped into an interesting thing with foreach. I really don't know, if
this is normal working, or why it is, so I got curious.
The script:
foreach ( $cats as&$c ) {
echo $c['id'];
if ( $c['id']< 5 )
Hi there
I think that foreach in your first example just knowns that this
should be the last loop (as the array only contains 1 element at
start) and so stops there.
In your 2nd example however the first loop isn't the last, so the
array get's checked again, and now there's another element, so...
On Jul 29, 2008, at 3:33 PM, Daniel Brown wrote:
On Tue, Jul 29, 2008 at 3:25 PM, Jason Pruim <[EMAIL PROTECTED]>
wrote:
function random($random){
$randomQuery = "SELECT * FROM `current` ORDER BY Rand() LIMIT
2";
$result = mysql_query($randomQuery);
$row[] = $result;
forea
You cannot do this:
$row[] = $result;
You need to loop around this:
$row = mysql_fetch_assoc($result);
Thank you,
Micah Gersten
onShore Networks
Internal Developer
http://www.onshore.com
Jason Pruim wrote:
> Hey Everyone...
>
> So I am attempting to pull 2 random records from a MySQL databa
On Tue, Jul 29, 2008 at 3:25 PM, Jason Pruim <[EMAIL PROTECTED]> wrote:
>
> function random($random){
>
>$randomQuery = "SELECT * FROM `current` ORDER BY Rand() LIMIT 2";
>
>$result = mysql_query($randomQuery);
> $row[] = $result;
>
>
> foreach($row as $key => $value) {
> $random[$k
On Nov 15, 2007, at 7:50 PM, Juan Marcelo Rodríguez wrote:
2007/11/15, Philip Thompson <[EMAIL PROTECTED]>:
On Nov 15, 2007 5:12 PM, Juan Marcelo Rodríguez <
[EMAIL PROTECTED]>
wrote:
Yes, I made a mistake in the first sentence.
The code is :
[...]
foreach ($equipos as $key => $val){
echo ""
$x = 0;
foreach ( $blah as $bleh ) {
$x = $x + 1;
print "$x: $bleh";
}
HI,
I'm working with an associative array, and generating its data a form. I use
foreach to loops the contents of the array and echo to print the table and
the data. Everything goes well, however I would like to add a counter
Juan Marcelo Rodríguez wrote:
I'm working with an associative array, and generating its data a form. I use
foreach to loops the contents of the array and echo to print the table and
the data. Everything goes well, however I would like to add a counter to
print the row's number.
The question : Am
On Nov 15, 2007 5:12 PM, Juan Marcelo Rodríguez <[EMAIL PROTECTED]>
wrote:
> Yes, I made a mistake in the first sentence.
>
> The code is :
> [...]
>
> foreach ($equipos as $key => $val){
>
> echo "";
> echo "1" . ""; // I would like to add the counter here
> reeplacing
> "1"
echo "".($key+1)."
Thanks.
I solved it using this :
$x = 0;
foreach ($equipos as $key => $val){
$x = $x + 1;
echo "";
echo $x . "";
2007/11/15, Michael McGlothlin <[EMAIL PROTECTED]>:
>
> $x = 0;
> foreach ( $blah as $bleh ) {
> $x = $x + 1;
> print "$x: $bleh";
> }
>
> > HI,
> > I'm working with an associative
2007/11/15, Philip Thompson <[EMAIL PROTECTED]>:
>
> On Nov 15, 2007 5:12 PM, Juan Marcelo Rodríguez <
> [EMAIL PROTECTED]>
> wrote:
>
> > Yes, I made a mistake in the first sentence.
> >
> > The code is :
> > [...]
> >
> > foreach ($equipos as $key => $val){
> >
> > echo "";
> > echo "1" . ""; //
Yes, I made a mistake in the first sentence.
The code is :
[...]
foreach ($equipos as $key => $val){
echo "";
echo "1" . ""; // I would like to add the counter here reeplacing
"1"
print "" . "";
echo $key . "";
print "" . "";
echo $val . "";
print "" . "";
}
?>
I use the array to generate the
On Sun, April 8, 2007 6:29 pm, [EMAIL PROTECTED] wrote:
> I have ..
>
> foreach( $_POST as $key ) {
> echo "$key";
> }
You are actually echoing out the VALUE, not the KEY...
> and that gives me
>
> item1
> item2
> item3
> item4
> item5
Unless your VALUE has "item1\nitem2\nitem3\nitem4\nitem5
;
> > Whois Results:
> >
> > >
> > foreach( $_POST as $key ) {
> >echo "$key";
> > }
> > ?>
> >
> >
> >
> >
> > - Original Message - From: "Lori Lay" <[EMAIL PROTECTED]>
";
}
?>
- Original Message - From: "Lori Lay" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Cc:
Sent: Monday, April 09, 2007 5:20 AM
Subject: Re: [PHP] foreach question
[EMAIL PROTECTED] wrote:
"both examples do the same thing.."
no, ex1 only
;
Cc:
Sent: Monday, April 09, 2007 5:20 AM
Subject: Re: [PHP] foreach question
[EMAIL PROTECTED] wrote:
"both examples do the same thing.."
no, ex1 only has 1
so outputs like..
item1item2item3item4item5
Where as I want this..
item1
item2
item3
item4
item5
ie a line break after e
o the list.
Lori
- Original Message - From: "Sebe" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Cc:
Sent: Monday, April 09, 2007 1:22 AM
Subject: Re: [PHP] foreach question
[EMAIL PROTECTED] wrote:
I have ..
foreach( $_POST as $key ) {echo "$key";
}
double quotes).
> >
> > - Original Message - From: "Sebe" <[EMAIL PROTECTED]>
> > To: <[EMAIL PROTECTED]>
> > Cc:
> > Sent: Monday, April 09, 2007 1:22 AM
> > Subject: Re: [PHP] foreach question
> >
> >
> >>
>
To: <[EMAIL PROTECTED]>
Cc:
Sent: Monday, April 09, 2007 1:22 AM
Subject: Re: [PHP] foreach question
[EMAIL PROTECTED] wrote:
I have ..
foreach( $_POST as $key ) {echo "$key";
}
and that gives me
item1
item2
item3
item4
item5
how do I write it to give me
item1
ite
;[EMAIL PROTECTED]>
Cc:
Sent: Monday, April 09, 2007 1:22 AM
Subject: Re: [PHP] foreach question
[EMAIL PROTECTED] wrote:
I have ..
foreach( $_POST as $key ) {echo "$key";
}
and that gives me
item1
item2
item3
item4
item5
how do I write it to give me
item1
item2
item3
item4
[EMAIL PROTECTED] wrote:
I have ..
foreach( $_POST as $key ) {echo "$key";
}
and that gives me
item1
item2
item3
item4
item5
how do I write it to give me
item1
item2
item3
item4
item5
Thanks
both examples do the same thing..
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