11 PM
- To: 'PHP List'
- Subject: RE: [PHP] Calculator Script
-
- Well, that would almost work, except that for something like (2x^2 - 8x -
- 41) / (x-7).
-
- A = 2
- B+A*R = 6
- C+B*R+A*R^2 = 1
-
- This is actually pretty close: 2x + 8 + (1 / (x-7))
-
- I guess there isn't any on
http://www.melchior.us
- -Original Message-
- From: Daniel Purdy [mailto:[EMAIL PROTECTED]
- Sent: Tuesday, April 20, 2004 4:58 PM
- To: Daniel Purdy; Stephen Craton
- Cc: PHP List
- Subject: RE: [PHP] Calculator Script
-
- [snip]
- A = 1
- B+A*R = 9
- C+B*R+A*R^2 = -7
-
- I get (b/3) + 3
hen Craton
- Cc: PHP List
- Subject: RE: [PHP] Calculator Script
-
-
- [snip]
- 3b = 3x - 0
-
- The book has this as an example too dealing with the program: (x^2 - 14x
- -
- 25) / (3x + 4)
- [/snip]
-
- Exactly. However the program is looking for x - r. there is no place to
- put a coefficie
[snip]
A = 1
B+A*R = 9
C+B*R+A*R^2 = -7
I get (b/3) + 3 - (7/3b) when I work it out by hand, and a teacher of
mine got the same thing. What exactly is this program finding, since it
obviously isn't any coefficients?
[/snip]
Acutally, looking at it further, it looks like it actually almost did it
[snip]
3b = 3x - 0
The book has this as an example too dealing with the program: (x^2 - 14x
-
25) / (3x + 4)
[/snip]
Exactly. However the program is looking for x - r. there is no place to
put a coefficient in front of the x.
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: [PHP] Calculator Script
-
-
- [snip]
- form ax^2 + bx + c by a binomial of the form x - r.
-
- One example I tried out was (b^2 + 9b - 7) / 3b.
- [/snip]
-
- I don't think that 3b is same form as x - r
-
-
-
-
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[snip]
form ax^2 + bx + c by a binomial of the form x - r.
One example I tried out was (b^2 + 9b - 7) / 3b.
[/snip]
I don't think that 3b is same form as x - r
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