Erk, my mistake, it's just 1 over x-7 or whatever because it's the
remainder. My bad. Thanks Daniel for all the help. :-)

Thanks,
Stephen Craton
http://www.melchior.us
 

- -----Original Message-----
- From: Stephen Craton [mailto:[EMAIL PROTECTED]
- Sent: Tuesday, April 20, 2004 5:11 PM
- To: 'PHP List'
- Subject: RE: [PHP] Calculator Script
- 
- Well, that would almost work, except that for something like (2x^2 - 8x -
- 41) / (x-7).
- 
- A = 2
- B+A*R = 6
- C+B*R+A*R^2 = 1
- 
- This is actually pretty close: 2x + 8 + (1 / (x-7))
- 
- I guess there isn't any one way to really make this program work, unless
- you
- have any ideas.
- 
- Thanks,
- Stephen Craton
- http://www.melchior.us
- 
- 
- - -----Original Message-----
- - From: Daniel Purdy [mailto:[EMAIL PROTECTED]
- - Sent: Tuesday, April 20, 2004 4:58 PM
- - To: Daniel Purdy; Stephen Craton
- - Cc: PHP List
- - Subject: RE: [PHP] Calculator Script
- -
- - [snip]
- - A = 1
- - B+A*R = 9
- - C+B*R+A*R^2 = -7
- -
- - I get (b/3) + 3 - (7/3b) when I work it out by hand, and a teacher of
- - mine got the same thing. What exactly is this program finding, since it
- - obviously isn't any coefficients?
- - [/snip]
- -
- - Acutally, looking at it further, it looks like it actually almost did it
- - correctly. If you take the results that the calculator gave you and
- - divide them by 3 then you get your answer. So the caluclator divides it
- - by b then you have to add in a part of it to divide by the 3. HTH!!
- -
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