Re: [PHP] Re: Eval var from query

2003-07-14 Thread Kevin Stone
- Original Message - From: "Shawn McKenzie" <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Sent: Monday, July 14, 2003 1:51 PM Subject: Re: [PHP] Re: Eval var from query > Thanks Kevin! That works great. It outputs: hi my name is Shawn > > Now if I want

Re: [PHP] Re: Eval var from query

2003-07-14 Thread Shawn McKenzie
PROTECTED] > > The string you send to eval() must be valid PHP code. So try this.. > > > > eval( 'echo "'.$data.'";'); > > > > - Kevin > > > > > > - Original Message - > > From: "Shawn McKenzie" <

Re: [PHP] Re: Eval var from query

2003-07-14 Thread Shawn McKenzie
e" <[EMAIL PROTECTED]> > To: <[EMAIL PROTECTED]> > Sent: Monday, July 14, 2003 1:15 PM > Subject: [PHP] Re: Eval var from query > > > > eval($data) > > > > returns Parse error: parse error, unexpected T_STRING in > > C:\apps\apache2\htdocs\te

Re: [PHP] Re: Eval var from query

2003-07-14 Thread Kevin Stone
;";'; $name = 'Shawn'; eval($code); // prints "hi may name is Shawn". Hope that makes it more clear. - Kevin - Original Message - From: "Kevin Stone" <[EMAIL PROTECTED]> To: "PHP-GENERAL" <[EMAIL PROTECTED]> Sent: Monday, J

Re: [PHP] Re: Eval var from query

2003-07-14 Thread Kevin Stone
The string you send to eval() must be valid PHP code. So try this.. eval( 'echo "'.$data.'";'); - Kevin - Original Message - From: "Shawn McKenzie" <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Sent: Monday, July 14, 2003 1:15 PM S

[PHP] Re: Eval var from query

2003-07-14 Thread Shawn McKenzie
eval($data) returns Parse error: parse error, unexpected T_STRING in C:\apps\apache2\htdocs\test\query.php(23) : eval()'d code on line 1 Thanks! Shawn "Shawn McKenzie" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] > How can I evaluate a var that is from a text field of a database?