Thanks Kevin!  That works great.  It outputs:  hi my name is Shawn

Now if I want to assign $data to another var, let's say $newdata and have it
eval the $name var inside of that.  How would that work?

Meaning I want to $newdata = hi my name is Shawn

Thanks!
Shawn

"Kevin Stone" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> The string you send to eval() must be valid PHP code.  So try this..
>
> eval( 'echo "'.$data.'";');
>
> - Kevin
>
>
> ----- Original Message -----
> From: "Shawn McKenzie" <[EMAIL PROTECTED]>
> To: <[EMAIL PROTECTED]>
> Sent: Monday, July 14, 2003 1:15 PM
> Subject: [PHP] Re: Eval var from query
>
>
> > eval($data)
> >
> > returns Parse error: parse error, unexpected T_STRING in
> > C:\apps\apache2\htdocs\test\query.php(23) : eval()'d code on line 1
> >
> > Thanks!
> > Shawn
> >
> > "Shawn McKenzie" <[EMAIL PROTECTED]> wrote in message
> > news:[EMAIL PROTECTED]
> > > How can I evaluate a var that is from a text field of a database?
> > Example:
> > >
> > > MySQL field `name` = hi my name is $name
> > >
> > > In my script I have:
> > >
> > > $name = "Shawn";
> > >
> > > After fetching a query result as an associative array I have the
> contents
> > of
> > > the `name` field in $data
> > >
> > > If I echo $data I get:  hi my name is $name
> > >
> > > I would like to get:  hi my name is Shawn
> > >
> > > TIA,
> > > Shawn
> > >
> > >
> >
> >
> >
> > --
> > PHP General Mailing List (http://www.php.net/)
> > To unsubscribe, visit: http://www.php.net/unsub.php
> >
> >
>
>



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