Perfect, thank you ... i knew I was overlooking something obvious ... the
query just flies now ...
On Mon, 18 Jun 2001, Tom Lane wrote:
> The Hermit Hacker <[EMAIL PROTECTED]> writes:
> >> Try adding ... AND n.nid = 15748 ... to the WHERE.
>
> > n.nid is the note id ... nl.id is the contact id
The Hermit Hacker <[EMAIL PROTECTED]> writes:
>> Try adding ... AND n.nid = 15748 ... to the WHERE.
> n.nid is the note id ... nl.id is the contact id ...
Ooops, I misread "n.nid = nl.nid" as "n.nid = nl.id". Sorry for the
bogus advice.
Try rephrasing as
FROM (note_links nl JOIN notes n ON (
On Mon, 18 Jun 2001, Tom Lane wrote:
> The Hermit Hacker <[EMAIL PROTECTED]> writes:
> > FROM note_links nl, notes n LEFT JOIN calendar c ON (n.nid = c.nid)
> > WHERE (n.type = 'A' OR n.type = 'N' OR n.type = 'H' OR n.type = 'C')
> > AND (nl.id = 15748 AND contact_lvl = 'c
I think that using INNER JOIN between nl and n (on n.nid=nl.nid) or
joining those tables in a subquery might work.
On Mon, 18 Jun 2001, The Hermit Hacker wrote:
> Is there some way to write the above so that it evaluates:
>
> WHERE (n.type = 'A' OR n.type = 'N' OR n.type = 'H' OR n.ty
The Hermit Hacker <[EMAIL PROTECTED]> writes:
> FROM note_links nl, notes n LEFT JOIN calendar c ON (n.nid = c.nid)
> WHERE (n.type = 'A' OR n.type = 'N' OR n.type = 'H' OR n.type = 'C')
> AND (nl.id = 15748 AND contact_lvl = 'company')
> AND n.nid = nl.nid
>
