On Thu, Jan 22, 2004 at 03:53:04AM +0100, A. Pagaltzis wrote:
: Good point; however, this means different way to think of the
: vector ops than we had so far. Basically, we're moving from the
: realm of vector ops to that of vectorized operands.
:
: In light of this, I think Austin's proposal of m
On Thu, Jan 22, 2004 at 03:57:26AM +0100, A. Pagaltzis wrote:
: * Piers Cawley <[EMAIL PROTECTED]> [2004-01-21 23:33]:
: > And once you go to an image based IDE and have access to the
: > bytecode of the code you're writing there's all *sorts* of
: > interesting things you can do. And that's before
> -Original Message-
> From: Larry Wall [mailto:[EMAIL PROTECTED]
> Sent: Thursday, January 22, 2004 12:50 PM
> To: Language List
> Subject: Re: Semantics of vector operations
>
>
> On Thu, Jan 22, 2004 at 03:57:26AM +0100, A. Pagaltzis wrote:
> : * Piers Cawley <[EMAIL PROTECTED]> [2004-
> -Original Message-
> From: Larry Wall [mailto:[EMAIL PROTECTED]
> Sent: Thursday, January 22, 2004 12:39 PM
> To: Language List
> Subject: Re: Semantics of vector operations
>
>
> On Thu, Jan 22, 2004 at 03:53:04AM +0100, A. Pagaltzis wrote:
> : Good point; however, this means different
> -Original Message-
> From: Jonathan Scott Duff [mailto:[EMAIL PROTECTED]
> Sent: Thursday, January 22, 2004 1:16 PM
> To: Austin Hastings
> Cc: Larry Wall; Language List
> Subject: Re: Semantics of vector operations (Damian)
>
>
> On Thu, Jan 22, 2004 at 01:10:23PM -0500, Austin Hasting
On Wed, Jan 21, 2004 at 08:51:33PM -0500, Joe Gottman wrote:
: Great, so
: $x = foo(), bar();
: means the same thing as
: $x = ( foo(), bar() );
No, we haven't changed the relative precedence of assignment and comma.
I've been tempted to, but I always come back to liking the parens
for vis
On Thu, Jan 22, 2004 at 01:10:23PM -0500, Austin Hastings wrote:
> In reverse order:
>
> > %languageometer.values ?+= rand;
>
> This is the same as
>
> all( %languageometer.values ) += rand;
>
> right?
It's the same as
$r = rand;
$_ += $r for %languageometer.values
On Thu, Jan 22, 2004 at 01:10:25PM -0500, Austin Hastings wrote:
: > -Original Message-
: > From: Larry Wall [mailto:[EMAIL PROTECTED]
: > I think some people will want to think of it one way, while others
: > will want to think of it the other way. If that's the case, the
: > proper place
Jonathan Scott Duff writes:
> On Thu, Jan 22, 2004 at 01:10:23PM -0500, Austin Hastings wrote:
> > In reverse order:
> >
> > > %languageometer.values Â+= rand;
> >
> > This is the same as
> >
> > all( %languageometer.values ) += rand;
> >
> > right?
Well, yes. It's also the same as e
* Larry Wall <[EMAIL PROTECTED]> [2004-01-22 18:40]:
> You might argue that we should force people to think of it one
> way or the other.
I wouldn't, because if I did I'd should've been talking to Guido
rather than you in the first place. :-)
And because I'm talking to you, I'll wonder whether ma
Austin Hastings writes:
> How do you handle operator precedence/associativity?
>
> That is,
>
>$a + $b + $c
>
> If you're going to vectorize, and combine, then you'll want to group. I
> think making the vectorizer a grouper as well kills two birds with one
> stone.
>
> $a + >>$b + $c<<
>
> -Original Message-
> From: Luke Palmer [mailto:[EMAIL PROTECTED]
> Sent: Thursday, January 22, 2004 3:52 PM
> To: Austin Hastings; Larry Wall; Language List
> Subject: Re: Semantics of vector operations (Damian)
>
>
> Jonathan Scott Duff writes:
> > On Thu, Jan 22, 2004 at 01:10:23PM
Austin Hastings writes:
> > Sortof. I think Larry was implying that rand returned an infinite list
> > of random numbers in list context. If not, then what he said was wrong,
> > because it would be sick to say that:
> >
> > (1,2,3,4,5) Â+Â foo()
> >
> > Calls foo() 5 times.
>
> Why would
Luke Palmer writes:
> > (1,2,3,4,5) +Â foo() # Maybe the same as above? What does
> > infix:+(@list,$scalar) do?
>
> Well, what does a list return in scalar context? In the presence of the
> C comma, it returns 5 for the last thing evaluated. In its absence, it
> returns 5 for the lengt
On Thu, Jan 22, 2004 at 11:25:41AM -0800, Larry Wall wrote:
> On Thu, Jan 22, 2004 at 01:10:25PM -0500, Austin Hastings wrote:
> : > -Original Message-
> : > From: Larry Wall [mailto:[EMAIL PROTECTED]
> : > I think some people will want to think of it one way, while others
> : > will want t
On Thu, Jan 22, 2004 at 01:28:42PM -0500, Austin Hastings wrote:
> > From: Jonathan Scott Duff [mailto:[EMAIL PROTECTED]
> > On Thu, Jan 22, 2004 at 01:10:23PM -0500, Austin Hastings wrote:
> > > In reverse order:
> > >
> > > > %languageometer.values ?+= rand;
> > >
> > > This is the same as
>
On Thu, Jan 22, 2004 at 02:28:09PM -0700, Luke Palmer wrote:
: Well, for being called "vector operators", they're ending up pretty
: useless as far as working with mathematical vectors.
Which is why I suggested calling them distributors or some such.
: As a
: mathematician, I'd want:
:
: @ve
On Thu, Jan 22, 2004 at 01:34:33PM -0600, Jonathan Scott Duff wrote:
: On Thu, Jan 22, 2004 at 11:25:41AM -0800, Larry Wall wrote:
: > Me? I handle it by making it an adverb on the base operator. :-)
:
: Does that mean it should get the colon? :)
Only if all adverbs in English end in -ly.
Of
- Original Message -
From: "Luke Palmer" <[EMAIL PROTECTED]>
To: "Austin Hastings" <[EMAIL PROTECTED]>
Cc: "Larry Wall" <[EMAIL PROTECTED]>; "Language List" <[EMAIL PROTECTED]>
Sent: Thursday, January 22, 2004 4:28 PM
Subject: [perl] Re: Semantics of vector operations
> Austin Hastings
On Thu, Jan 22, 2004 at 08:08:13PM -0500, Joe Gottman wrote:
:I just realized a potential flaw here. Consider the code
: $a >>= 1;
:
:Will this right-shift the value of $a one bit and assign the result to $a
: (the current meaning)? Or will it assign the value 1 to each element i
Luke Palmer <[EMAIL PROTECTED]> writes:
> @A »+« @B # One-at-a-time
> @A «+» @B # Outer product
>
> Or something. Hmm, then both:
>
> @A »+ $b
> @A «+ $b
There is a page you may find inspiring:
http://www.ritsumei.ac.jp/~akitaoka/index-e.html
Sorry, I could n
Larry Wall writes:
> On Thu, Jan 22, 2004 at 08:08:13PM -0500, Joe Gottman wrote:
> :I just realized a potential flaw here. Consider the code
> : $a >>= 1;
> :
> :Will this right-shift the value of $a one bit and assign the result to $a
> : (the current meaning)? Or will it assig
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