> -----Original Message----- > From: Jonathan Scott Duff [mailto:[EMAIL PROTECTED] > Sent: Thursday, January 22, 2004 1:16 PM > To: Austin Hastings > Cc: Larry Wall; Language List > Subject: Re: Semantics of vector operations (Damian) > > > On Thu, Jan 22, 2004 at 01:10:23PM -0500, Austin Hastings wrote: > > In reverse order: > > > > > %languageometer.values ?+= rand; > > > > This is the same as > > > > all( %languageometer.values ) += rand; > > > > right? > > It's the same as > > $r = rand; > $_ += $r for %languageometer.values > > Your junction looks like it should work but I think you're really > adding the random number to the junction, not the elements that compose > the junction thus none of %languageometer.values are modified.
It would be disappointing if junctions could not be lvalues. > > And is this > > > > > %languageometer.values ?+=? rand; > > > > the same as > > > > all( %languageometer.values ) += one( rand ); > > I don't think so. It's like: > > $_ += rand for %languageometer.values > > perhaps if you had: > > $j |= rand for (0..%languageometer.values) > any(%languageometer.values) += $j; > > Though I'm not sure what that would mean. > > I don't think junctions apply at all in vectorization. They seem to > be completely orthogonal. I'm curious if that's true, of if they're two different ways of getting to the same data. (At least in the one-dimension case.) =Austin
