)
Nope. Read the manual.
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Mark Cogan[EMAIL PROTECTED] +1-520-881-8101
ArtToday www.arttoday.com
At 11:05 PM 8/15/00 -0500, Jonathan Scott Duff wrote:
>On Tue, Aug 15, 2000 at 08:59:25PM -0700, Mark Cogan wrote:
> > At 11:43 PM 8/15/00 -0400, Chaim Frenkel wrote:
> > >Counter example:@a = \($a, $b, $c);
> >
> > I guess I'm missing the point; ho
At 11:43 PM 8/15/00 -0400, Chaim Frenkel wrote:
> >>>>> "MC" == Mark Cogan <[EMAIL PROTECTED]> writes:
>
>MC> What should:
>MC> @a = defined @a;
>MC> return?
>
>Counter example:@a = \($a, $b, $c);
I guess I'm missing the p
;
>or perhaps a modifier?
>
> @result = @a || @b forall;
>
>(Blech, that just doesn read right.)
Perhaps we just need a two-list map, which aliases $a and $b like sort():
@result = map {$a || $b} @a,@b;
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Ma
At 12:39 PM 8/16/00 +1000, Jeremy Howard wrote:
>Mark Cogan wrote:
> > At 05:47 PM 8/15/00 -0600, Nathan Torkington wrote:
> > >Jeremy Howard writes:
> > > > @result = @a || @b;
> > > >
> > > > Which applies '||' component-wise
I want to iterate over @a, I should have to do so
explicitly, with a for() or map().
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Mark Cogan[EMAIL PROTECTED] +1-520-881-8101
ArtToday www.arttoday.com
>whether it is
>relevant to this RFC.
Camel, 2e, page 50 :
"The => operator is just a synonym for a comma, but it's more visually
distinctive, and it also quotes any bare identifiers to the left of it..."
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Mark Cogan[EMAIL PROTECTED] +1-520-881-8101
ArtToday www.arttoday.com
