Now, can it happen that xas_try_split() would ever perform a partial split in
any way, when invoked from __split_unmapped_folio(), such that we run into the
do { } while(); loop and fail with -ENOMEM after already having performed
changes -- xas_update().
Or is that simply impossible?
Right
On 18 Feb 2025, at 10:44, David Hildenbrand wrote:
> On 17.02.25 23:05, Zi Yan wrote:
>> On 17 Feb 2025, at 16:44, David Hildenbrand wrote:
>>
>>> On 11.02.25 16:50, Zi Yan wrote:
It is a preparation patch for non-uniform folio split, which always split
a folio into half iteratively, and
On 17.02.25 23:05, Zi Yan wrote:
On 17 Feb 2025, at 16:44, David Hildenbrand wrote:
On 11.02.25 16:50, Zi Yan wrote:
It is a preparation patch for non-uniform folio split, which always split
a folio into half iteratively, and minimal xarray entry split.
Currently, xas_split_alloc() and xas_sp
On 17 Feb 2025, at 16:44, David Hildenbrand wrote:
> On 11.02.25 16:50, Zi Yan wrote:
>> It is a preparation patch for non-uniform folio split, which always split
>> a folio into half iteratively, and minimal xarray entry split.
>>
>> Currently, xas_split_alloc() and xas_split() always split all s
On 11.02.25 16:50, Zi Yan wrote:
It is a preparation patch for non-uniform folio split, which always split
a folio into half iteratively, and minimal xarray entry split.
Currently, xas_split_alloc() and xas_split() always split all slots from a
multi-index entry. They cost the same number of xa_
On 11 Feb 2025, at 19:57, Zi Yan wrote:
> On 11 Feb 2025, at 10:50, Zi Yan wrote:
>
>> It is a preparation patch for non-uniform folio split, which always split
>> a folio into half iteratively, and minimal xarray entry split.
>>
>> Currently, xas_split_alloc() and xas_split() always split all slo
On 11 Feb 2025, at 10:50, Zi Yan wrote:
> It is a preparation patch for non-uniform folio split, which always split
> a folio into half iteratively, and minimal xarray entry split.
>
> Currently, xas_split_alloc() and xas_split() always split all slots from a
> multi-index entry. They cost the sam
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