;> Is it possible to derive the correct default print function for a grob?
> >>
> >> For example, if I want to get the stencil of a hairpin, I know the
> >> function
> >> is called "ly:hairpin::print", but for accidentals, it's
> >> &
2015-01-20 22:49 GMT+01:00 Thomas Morley :
> 2015-01-20 22:30 GMT+01:00 tisimst :
>> Is it possible to derive the correct default print function for a grob?
>>
>> For example, if I want to get the stencil of a hairpin, I know the function
>> is called "ly:hairpin::p
2015-01-20 22:30 GMT+01:00 tisimst :
> Is it possible to derive the correct default print function for a grob?
>
> For example, if I want to get the stencil of a hairpin, I know the function
> is called "ly:hairpin::print", but for accidentals, it's
> "ly:accide
Is it possible to derive the correct default print function for a grob?
For example, if I want to get the stencil of a hairpin, I know the function
is called "ly:hairpin::print", but for accidentals, it's
"ly:accidental-interface:print".
I'd like to be able to g
The problem is probably that stems and perhaps some other objects as well,
determine their position based on the position of the corresponding note
head,
so when you remove that particular print-function, you also remove a
prerequisite
for other parts of LilyPond to work. However, in general
In the docs for #'transparent, it says "This is almost the same as
setting print-function to #f, but this retains the dimensions of this
grob, which means that grobs can be erased individually." Since I
actually *want* to blow away the dimensions of the grob, this
alternative s
