Is it possible to derive the correct default print function for a grob? For example, if I want to get the stencil of a hairpin, I know the function is called "ly:hairpin::print", but for accidentals, it's "ly:accidental-interface:print".
I'd like to be able to get the right one automatically (in scheme) without needing to specify them all and use conditionals to figure out the right one. Any suggestions? I'm not sure if this is even possible, and I can deal with it if it's not, but I'd rather not if I can help it. Thanks, Abraham -- View this message in context: http://lilypond.1069038.n5.nabble.com/Derive-the-correct-print-function-of-a-grob-tp170809.html Sent from the User mailing list archive at Nabble.com. _______________________________________________ lilypond-user mailing list lilypond-user@gnu.org https://lists.gnu.org/mailman/listinfo/lilypond-user
