Graham Percival wrote:
There is a \strut command to do this, but last time I looked it was
broken.
\strut certainly doesn't appear to do anything now. What is is supposed
to do? If it's the same thing as \hspace #0 or #1, then wouldn't it
just be
Yes, I'm curious which baboon coded this,
... hey, how does hspace #0 do anything? if amount=0, then surely
\hspace shouldn't do anything?
(if (> amount 0)
(ly:make-stencil "" (cons 0 amount) '(-1 . 1))
(ly:make-stencil "" (cons amount amount) '(-1 . 1
Hint: Translated to C, this means something like
if (amount > 0)
On 27-Aug-05, at 1:00 PM, Han-Wen Nienhuys wrote:
Mats Bengtsson wrote:
As far as I can understand, a \hspace #0 gives a markup that is
0pt wide but has a height that is the total height (i.e. the depth +
the
height) of the characters in the font. That's the only way I can
explain
what happ
Mats Bengtsson wrote:
As far as I can understand, a \hspace #0 gives a markup that is
0pt wide but has a height that is the total height (i.e. the depth + the
height) of the characters in the font. That's the only way I can explain
what happens in your example. However, I'm not sure if that's a g
As far as I can understand, a \hspace #0 gives a markup that is
0pt wide but has a height that is the total height (i.e. the depth + the
height) of the characters in the font. That's the only way I can explain
what happens in your example. However, I'm not sure if that's a good
behaviour for \null
Could \null mimic the behavior of \hspace #0 ? It would be nice if we
could use it in the following way:
\layout{ raggedright=##t}
{ \fatText
c4^\markup{ \null aaa}
c4^\markup{ \null qqq}
c4^\markup{ \hspace #0 aaa}
c4^\markup{ \hspace #0 qqq}
}
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