or try the
> after() method (http://docs.jquery.com/Manipulation/after#content)
>
>
>
> On Tue, Aug 18, 2009 at 10:52 AM, Renato Untalan wrote:
>
> > I'm trying to clone an element, more specifically a fieldset tag.
>
> > Original HTML:
> > Hello World.
Thank you Ed!
On Aug 18, 11:05 am, Ed Allen wrote:
> Replace .append() with .after() I think.
>
> On Aug 18, 10:52 am, Renato Untalan wrote:
>
> > I'm trying to clone an element, more specifically a fieldset tag.
>
> > Original HTML:
> > Hello World.
&g
I'm trying to clone an element, more specifically a fieldset tag.
Original HTML:
Hello World.
Javascript:
$("fieldset").each(function(count,item){
var fieldsetBlock = $(this).append($(this).clone())
})
Desired HTML:
Hello World.
Hello World.
Undesired Result:
Hello World.
Hell
This is good to here.
I just implemented tablesort, at which there will be up to 1000 rows.
Glad to know that 400 sorts very quickly.
On Apr 9, 5:19 pm, csi95 wrote:
> Okay, my bad here.
>
> Thanks to the one-on-one help of one of the great members here, I was able
> to find the problem.
>
> It
I'm having trouble parsing JSON in Javascript.
The response i'm getting from PHP when making a request is:
[
{'name': 'John', 'lastName': 'Doe','age':'25', 'height': '170',
'weight': '120'},
{'name': 'Jane', 'lastName': 'Doe','age':'26', 'height': '175',
'weight': '121'},
{'name': 'Jack', 'lastNa
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