Here I am again with another question...
How do I check that a given string: (hd0), (hd1,0), (hd1) is an
existent drive?
I supposed that I had to use grub_disk_open because I did not want to
use grub_device_open can open (hd1,0) and (hd1,0) is not a drive but a
partition.
I am wondering if there is plans for Grub 2 to be able to be compiled
and run in a 64 bit enviroment. I am a part of the Cross-LFS Dev. team,
and Under the pure 64 bit system, we have to use a 32 static version of
grub compiled on a 32 computer in order to get it to boot, or use
*Cough* lilo.
At Sun, 17 Jun 2007 17:11:44 -0600,
David Broadfoot wrote:
> I am wondering if there is plans for Grub 2 to be able to be compiled
> and run in a 64 bit enviroment. I am a part of the Cross-LFS Dev. team,
> and Under the pure 64 bit system, we have to use a 32 static version of
> grub compiled o
