if you get into the fmt.println, you will see the output device is
os.Stdout, any println call will direct output into it nodelay
在 2017年1月21日星期六 UTC+8上午11:34:09，Rodolfo Azevedo写道：
>
> Hi all,
>
> I have a question, interesting:
>
> Why the executes is diferente in these both situations?
>
> Exec
0:00 UTC.
> sec int64
> // nsec specifies a non-negative nanosecond
> // offset within the second named by Seconds.
> // It must be in the range [0, 9].
> nsec int32
> loc *Location
> }
>
> On Friday, November 25, 2016 at 3:38:23 PM UTC+8, Xu Lei wro
os: windows7
version: go version go1.7 windows/amd64
On Friday, November 25, 2016 at 4:24:52 PM UTC+8, Dave Cheney wrote:
>
> You might want to try eTime.Sub(sTime) which returns a time.Duration which
> can print itself.
>
> Which operating system are you using? Which version of Go are you usin
thanks for replying!!!
the answers are great
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2016-11-25 15:36:21.9983037 +0800 CST : [Success for beacons.gvt2.com. for 38]
2016-11-25 15:36:22.0083043 +0800 CST : [Success for timgsa.baidu.com. for
-960]
2016-11-25 15:36:22.0153047 +0800 CST : [Success for sp0.baidu.com. for -953]
2016-11-25 15:36:22.0153047 +0800 CST : [Success for s
..
sTime := time.Now().Nanosecond()
defer func() {
eTime := time.Now().Nanosecond()
debug("Success for ", qname, "for", (eTime-sTime)/100)
}()
..
i got negative value for (eTime - sTime) when defer function calls
is there any thing
