On Do, 2015-08-06 at 01:11 -0700, Chris Moody wrote:
> Hi Marc,
>
> Thanks for the feedback. One more question and I think I'm done for now
> and able to finish the program I'm writing:
>
> If FindNode does not locate a node with the given name, what does it
> return?
I don't know. It looks li
Hi Marc,
Thanks for the feedback. One more question and I think I'm done for now
and able to finish the program I'm writing:
If FindNode does not locate a node with the given name, what does it
return?
Thanks,
Chris
On 07/24/2015 01:34 PM, Marc Santhoff wrote:
On Fr, 2015-07-24 at 11:57
On Fr, 2015-07-24 at 11:57 -0700, Chris Moody wrote:
> Would it be easiest to introduce a fourth element to the XML that says
> how many children the 3rd element has? Or is there an easy way already
> to get this and just run a for next loop to read each child?
Maybe sth. like this would do:
Hi all,
For the app I'm writing, it will have 3 elements in the XML document it
reads. The first 2 will only have one child element. The third one will
be from 1 to whatever.
I'm also designing the app that will create the XML file for the app to
read also, so a couple of questions:
Would
