On Fr, 2015-07-24 at 11:57 -0700, Chris Moody wrote:
> Would it be easiest to introduce a fourth element to the XML that says
> how many children the 3rd element has? Or is there an easy way already
> to get this and just run a for next loop to read each child?
Maybe sth. like this would do:
<counted_element count=3>
<child>1>/child>
<child>2>/child>
<child>3>/child>
</counted_element>
or similar. Besides making the count an attribute of the root node of
counted elements you could simply use a standard pascal loop:
n: XMLNode;
{ this is only pseude code ... }
while (xmldoc.hasMoreChilds()) do begin
n := getChild();
... process n ...
end:
For real code http://wiki.freepascal.org/XML_Tutorial mwill help.
HTH,
Marc
--
Marc Santhoff <m.santh...@web.de>
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