models.py
class Geolocation(models.Model):
user = models.ForeignKey(User, null=False)
location_latitude = models.CharField('Latitude', max_length=20, null=True,
blank=True)
location_longitude = models.CharField('Longitude', max_length=20,
null=True, blank=True)
In my application,i a
h lat & long.
> You could compute this using a standard norm calculation but its slow
> compared to using a native DB query.
>
>
> On Tue, Jun 4, 2013 at 8:49 AM, Sivaram R
> > wrote:
>
>> models.py
>>
>> class Geolocation(models.Model):
>>
Hi,i am doing printers,print-out functionality.So the data what ever i want
to print are rendered in a template called print.html.So while method call
it is rendering that template as print-out format.I don't know how to set a
background image for that print-out template.Is it same as table back
results trying in a more appropriate group or forum.
>
> Thomas
>
>
> On Thu, Jun 13, 2013 at 2:12 PM, Sivaram R
> > wrote:
>
>> Hi,i am doing printers,print-out functionality.So the data what ever i
>> want to print are rendered in a template called print
forms.py
DATE_INPUT_FORMAT = (
('%d/%m/%Y','%m/%d/%Y')
)
class ReportDatetimeForm(forms.ModelForm):
manual_date = forms.DateField(input_formats = DATE_INPUT_FORMAT,
widget=forms.DateInput(attrs={'size':'15','id':'datepicker','readonly':'readonly'}))
class Meta:
model = Report
fields = ['
I am developing an application in Django.It is developed to create new
report ,edit the report and delete the report.
Consider i am having 5 pages in my app and if i completed edit in 1st two
pages,now i am saving the report so,it will be saved as draft.For editing
the draft report,a button
who.html
{% csrf_token %}
{{report_person.report_person.name }}
{{report_person.info.first_aid}}{{report_person.info.first_aid.label}}
{{report_person.info.sick_bay}}{{report_person.info.sick_bay.label}}
views.py
def calender(request):
""
settingsform = SettingsForm(instance=settings)
if request.method == 'POST':
reportform = ReportDateTimeForm(request.POST, instance=report)
if reportform.is_valid():
report = reportform.save(commit=False)
re
know why this is happening and how to solve this.
Thanks
On Thursday, July 4, 2013 5:20:52 PM UTC+5:30, Sivaram R wrote:
>
> views.py
>
> def calender(request):
>
> """"""
> settingsform = Sett
I am developing an django app,now the problem is after successfull login,it
takes me to account/profile which is no longer available in django
urls.But after removing that account/profile and hit enter it is taking
inside the application.Do i need to frame a method and page for that or how
to
IRECT_URL = "/"
>
>
> 2013/7/5 Sivaram R >
>
>> I am developing an django app,now the problem is after successfull
>> login,it takes me to account/profile which is no longer available in
>> django urls.But after removing that account/profile and hit enter it is
&
I am learning django.
I came accross the django doc about session.
My question is for example if i am having the below models.py
class Report(models.Model):
user = models.ForeignKey(User, null=False)
report_number = models.CharField('Incident Number', max_length=100)
device_id = mode
forms.py
PERSON_ACTIONS = (
('1', '01.Allowed to rest and returned to class'),
('2', '02.Contacted parents /guardians'),
('3', '02a.- Unable to Contact'),
('4', '02b.Unavailable - left message'),)
class PersonActionsForm(forms.ModelForm):
action = forms.MultipleChoiceField(widge
Hi,can i get any answer or let me know the way to do this.
Thanks
On Monday, July 15, 2013 7:46:43 PM UTC+5:30, Sivaram R wrote:
>
> forms.py
>
> PERSON_ACTIONS = (
> ('1', '01.Allowed to rest and returned to class'),
> ('2', '02.Cont
- check if this was the selected choice from db, or
> from POST data
>
>
> And then you return this to your template and create custom html tags for
> this...
>
> Enjoy
>
>
> Dne pondělí, 15. července 2013 16:16:43 UTC+2 Sivaram R napsal(a):
>>
>> forms.p
+5:30, Tom Evans wrote:
>
> On Mon, Jul 15, 2013 at 3:16 PM, Sivaram R >
> wrote:
> > forms.py
> >
> > PERSON_ACTIONS = (
> > ('1', '01.Allowed to rest and returned to class'),
> > ('2', '02.Contacted
By default from project directory by running manage.py createsuperuser comment
i am able to create a superuser,but the .is_superuser flag is the default
django flag to differ superuser or other user.
I don't what to use that because i am using that flag throughout the
application to show sett
Have you given the correct url? for file
call ?
Regards,
Sivaram R
On Thursday, July 18, 2013 11:41:29 PM UTC+5:30, Harjot Mann wrote:
>
> http://tny.cz/ab1b86eb
> Here are my views for creating pdfs but I am getting this error:
>
> HTTPError at /report/myview/
>
> HTTP
Hi,
I would like to create username in django user model as random string.I
am using models form to save the user profile in that model.
In models form i am having the fields like
first_name,last_name,email_id,password,is_active,is_staff and is_superuser
and username.
While saving th
I have views.py to show the form instance and update the instance.
On edit the form data,all other field are showing the correct
value,password field is showing the entire hashed value from database and
not the entered password.
Is any way to show the entered password instead of hashed value
original
value entered.How to decrypt that hashed value to original value.
Thanks
On Wednesday, September 18, 2013 10:59:30 PM UTC+5:30, Kakar wrote:
>
> R u looking at the password from the admin?
>
>
>
> Sivaram R > wrote:
>
>
> I have views.py to show the form in
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