Hi Desh,
Welcome to Django :)
Like Adam said, you should unsubscribe from the django-developers mailing
list for now. That list is for people who are actually working on the
Django framework itself.
The django-users mailing list is the one where people who are learning to
use Django communicate.
Hi Balaji,
You can convert your web app into a PWA to gain maximum benefit. Just look
it up.
Data shows that PWAs are the way to go.
Kind regards,
- SD
On Tue, Jan 7, 2020, 19:47 Balaji Shetty wrote:
> Hi
>
> Currently i deployed application on pythonanywhere. It is online office
> file man
Hey guys. SOS please. How do I write a URL pattern for a URL like this?
weather/?current_location=-33.927407,18.415747&booking_location=-32.927407,19.415747
When I do reverse(‘weather’, kwargs={‘current_location’: some_value,
'booking_ location’: another_value}) I am getting a NoReverseMatch
exce
Thanks Jason.
Kind regards,
- SD
On Mon, Jan 13, 2020, 16:28 Jason wrote:
> The url resolver does not include GET query params in a URL, you need to
> add them manually after the string.
>
> for example
>
> url =
> f"{reverse('weather')}/?current_location={some_value}&booking_location={an
I have a dictionary which contains one item (“current_location”, which is a
nested dict) and I would like to access that nested dict. However, I cannot
use the key as the code will break if a different key is passed, e.g.
“different_location”.
How can I access the first item in a dictionary withou
#x27;m sure that there are other ways. There is certainly at least a way to
> play with the iterator protocol without using "for", but it may be harder
> to read. You could put break at the end of the loop above to make it more
> apparent that it only runs once.
>
> On Mo
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