I ended up using `dict[next(iter(dict))]`
I am getting the dict as one of two dicts nested in a list from a weather
service API. I do this using a list comprehension to call the API with
coordinates for each location in another list. A mouthful.
`resp = [fetch_api_data(location, request_id) for location in
REQUEST_LOCATIONS]`
I then cycle through the list and, for each dict, persist a WeatherRequest
instance to db like so:
`
for item in weather_data:
data = item[next(iter(item))]
WeatherRequest(
date=data['date'],
request_id=data['request_id'],
request_location=data['request_location'],
type_icon=data['type_icon'],
description=data['description'],
temperature=data['temperature'],
wind_speed=data['wind']['speed'],
wind_bearing=data['wind']['bearing'],
wind_gust=data['wind']['gust'],
rain_prob=data['rain_prob'],
latitude=data['latitude'],
longitude=data['longitude']
).save()
`
Thanks.
Kind regards,
- SD
On Mon, Jan 27, 2020 at 2:51 PM Bill Freeman <ke1g...@gmail.com> wrote:
> Note that these give the only value. This won't work if you have more
> than one value in the dict, since you won't know which you will get. Where
> d is the dict:
>
> list(d.values())[0]
>
> or
>
> for i in d.values():
> # use i here
> print(i)
>
> or
>
> d[list(d)[0]]
>
> I'm sure that there are other ways. There is certainly at least a way to
> play with the iterator protocol without using "for", but it may be harder
> to read. You could put break at the end of the loop above to make it more
> apparent that it only runs once.
>
> On Mon, Jan 27, 2020 at 6:58 AM S D <zebr...@gmail.com> wrote:
>
>> I have a dictionary which contains one item (“current_location”, which is
>> a nested dict) and I would like to access that nested dict. However, I
>> cannot use the key as the code will break if a different key is passed,
>> e.g. “different_location”.
>>
>> How can I access the first item in a dictionary without using a key? The
>> dict looks like this:
>>
>> `
>> {'current_location': {'date': '2020-01-27T10:28:24.148Z', 'type_icon':
>> 'partly-cloudy-day', 'description': 'Mostly Cloudy', 'temperature': 68.28,
>> 'wind': {'speed': 10.48, 'bearing': 178, 'gust': 12.47}, 'rain_prob': 0.02,
>> 'latitude': '-33.927407', 'longitude': '18.415747', 'request_id': 31364,
>> 'request_location': 'Current location'}}
>> `
>>
>> Kind regards,
>> - SD
>>
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