On 15-Nov-07, at 7:38 PM, Greg_IAP wrote:
> With this solution a press button is created and the browser wants to
> open the url: ".../spica/cgi-bin/ingestion.py" by pressing it.
link: Click to launch script
url: r'^ingestion/$'
view:
def ingestion(request):
pythonscripthere
..
On Nov 15, 2:08 pm, Greg_IAP <[EMAIL PROTECTED]> wrote:
> Hi
> I just want to launch a python script from my web page done with
> django.
> 2 ways to do this-> by a form included in "mytemplate.html" for
> example, like this:
>
> method="post">
> maxlength="50">
>
>
>
> With this solution a
I am not sure I understand you question ... you want to launch a
python script from a django url ? you can just import the script into
urls.py and running from a url.
On Nov 15, 12:03 pm, Greg_IAP <[EMAIL PROTECTED]> wrote:
> Could anyone answer my question of yesterday?
>
> my problem is the act
Hi
I just want to launch a python script from my web page done with
django.
2 ways to do this-> by a form included in "mytemplate.html" for
example, like this:
With this solution a press button is created and the browser wants to
open the url: ".../spica/cgi-bin/ingestion.py" by pressing i
Hi
i just want to launch a python script from my web page done with
django:
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Could anyone answer my question of yesterday?
my problem is the action of the form (to launch python script from my
web page) which can be matched by urlpattern in urls.py
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